The mass of water produced when 4.86 g of butane(C4H10) react with excess oxygen is calculated as below
calculate the moles of C4H10 used = mass/molar mass
moles = 4.86g/58 g/mol =0.0838 moles
write a balanced equation for reaction
2 C4H10 + 13 O2 = 8 CO2 + 10 H2O
by use of mole ratio between C4H10 to H2O which is 2:10 the moles of
H20= 0.0838 x10/2 = 0.419 moles of H2O
mass = moles x molar mass
=0.419 molx 18 g/mol = 7.542 grams of water is formed
Answer:
Answer: 882mmHg
Explanation:
In a closed-end manometer, the gas added is under a pressure that is measured against atmospheric pressure. The difference in pressure between both gases is equal to the difference in mercury levels. Thus, the pressure of the argon can be:
783 mmHg - 96.0mmHg = 687mmHg
783 mmHg - 96.0mmHg = 879mmHg
Based on the options, the possible answer (The nearest to the second value) is:
<h3>Answer: 882mmHg</h3>
Answer:
c iodine
Explanation:
fluorine is a halogen group element like Bromine, Iodine,Astatine,Chloride
Answer:
Molar mass = 99 g/mol
Explanation:
Phosgene contains carbon, oxygen and chlorine atoms. Its molecular formular is; COCl2
The molar mass is given as the sum off the individual atomic mass of the elements in the compound.
Molar mass = C + O + 2Cl
Molar mass = 12 + 16 + 2(35.5)
Molar mass = 99 g/mol
Answer:
A. State of matter of the substance.
Explanation:
During a chemical change, the composition of matter always changes.
