Question

Yeast and other organisms can convert glucose (C6H12O6) to Ethanol (CH3CH2OH) through a process called Alcoholic Fermentation. The Net reaction is:
C6H12O6------2C2H5OH(l) +2CO2(g)

Calculate the mass of glucose required to produce 2.25L of CO2 measured at P=1 atm and T=295k

Answer 1

Answer:

The answer to your question is 8.28 g of glucose

Explanation:

Data

Glucose  (C₆H₁₂O₆) = ?

Ethanol (CH₃CH₂OH)

Carbon dioxide (CO₂) = 2.25 l

Pressure = 1 atm

T = 295°K

Reaction

                             C₆H₁₂O₆    ⇒    2C₂H₅OH(l) +2CO₂(g)

- Calculate the number of moles

                             PV = nRT

Solve for n

                             $n = \frac{PV}{RT}$

Substitution

                             $n = \frac{(1)(2.25)}{(0.082)(295)}$

Simplification

                            n = 0.092

- Calculate the mass of glucose

                         1 mol of glucose --------------- 2 moles of carbon dioxide

                          x                         --------------- 0.092 moles

                          x = (0.092 x 1) / 2

                          x = 0.046 moles of glucose

Molecular weight of glucose = 180 g

                       180 g of glucose ---------------  1 mol

                         x  g                    ---------------0.046 moles

                         x = (0.046 x 180) / 1

                         x = 8.28 g of glucose