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aliya0001 [1]
3 years ago
6

State the purpose of respiration.​

Chemistry
2 answers:
iren2701 [21]3 years ago
8 0

Answer:

The purpose of respiration is to supply the body with oxygen and eliminate carbon dioxide. Oxygen is essential for cellular respiration as cells cannot exist in the absence of it. The human lungs are the organs responsible for respiration.

Explanation:

Respiration refers to a person’s breathing and the movement of air into and out of the lungs. The respiratory system provides oxygen to body tissues for cellular respiration, removes the waste product carbon dioxide, and helps maintain acid–base balance. Inspiration is the process that causes air to enter the lungs, and expiration is the process that causes air to leave the lungs . A respiratory cycle (or one breath while you are measuring respiratory rate) is one sequence of inspiration and expiration.

navik [9.2K]3 years ago
7 0
To provide for the exchange of oxygen and carbon dioxide between the atmosphere and the blood
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If copper carbonate system is heated for too short a time, what will you notice for mass percent of copper be too large or too s
sammy [17]

Answer:

The mass percent of copper as element is the same.

Explanation:

First of all we need the reaction that is presented below:

CuCO_{3 (s)} +Heat → CuO_{(s)} + CO_{2 (g)}

The mass percent of copper (Cu) as element is the same because of during the reaction the element only transform its nature from copper carbonate (CuCO_{3 (s)}) to copper oxide (CuO_{(s)}), the latter is a solid and will remain in the system.

On the other hand, you will note that the global percentage mass will be small because of the reaction produce (CO_{2 (g)}) that is a gas and this one will escape for the system.  

Have a great day!

3 0
3 years ago
What is the % dissociation of a solution of acetic acid if at equilibrium the solution has a pH = 4.74 and a pKa = 4.74?
Ymorist [56]

Answer:

\% diss = 50\%

Explanation:

Hello there!

In this case, when considering weak acids which have an associated percent dissociation, we first need to set up the ionization reaction and the equilibrium expression:

HA\rightleftharpoons H^++A^-\\\\Ka=\frac{[H^+][A^-]}{[HA]}

Now, by introducing x as the reaction extent which also represents the concentration of both H+ and A-, we have:

Ka=\frac{x^2}{[HA]_0-x} =10^{-4.74}=1.82x10^{-5}

Thus, it is possible to find x given the pH as shown below:

x=10^{-pH}=10^{-4.74}=1.82x10^{-5}M

So that we can calculate the initial concentration of the acid:

\frac{(1.82x10^{-5})^2}{[HA]_0-1.82x10^{-5}} =1.82x10^{-5}\\\\\frac{1.82x10^{-5}}{[HA]_0-1.82x10^{-5}} =1\\\\

[HA]_0=3.64x10^{-5}M

Therefore, the percent dissociation turns out to be:

\% diss=\frac{x}{[HA]_0}*100\% \\\\\% diss=\frac{1.82x10^{-5}M}{3.64x10^{-5}M}*100\% \\\\\% diss = 50\%

Best regards!

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2 years ago
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The formula for Density is:

D = M / V.

Another way to remember the formula for Density is to remember "Mass per unit of volume".

I hope this helps!
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