A 30 wt % solution of NaOH is diluted in a mixer to 5 wt%. If the streams entering and leaving the mixer are at 40 oC, find the
1 answer:
Explanation:
It is given that 100 kg feed solution contains 30 wt% solution NaOH. Hence, feed contains 70 kg of water and 30 kg of NaOH.
Therefore, mixer outlet shows 5 wt% NaOH.
Let us assume that the mixture outlet be F kg so, by applying mass balance of NaOH we get the value of force as follows.
= 30
F = 600 Kg
In that 30 kg is NaOH and 570 kg is water which also means that initially water present is 70 kg. And, additional water added is 500 kg .
Thus, water feed rate is 500 kg/hr.
You might be interested in
682mL
Explanation:
Given parameters:
Initial volume of air = 600mL
Initial temperature = 20°C
Final temperature = 60°C
Unknown:
Final volume = ?
Solution:
To solve this problem, we apply Charles's law';
Charles's law states that "at constant pressure, the volume of a given mass of gas is directly proportional to its temperature. "
Mathematically;
V₁ is the initial volume of air
T₁ is the initial temperature of air
V₂ is the final volume of air
T₂ is the final temperature of air
To proceed in solving this problem, we need to convert the given temperature to Kelvin;
T K = 273 + T°C
T₁ = 273 + 20 = 293K
T₂ = 273 + 60 = 333K
now input the parameters;
V₂ = 682mL
learn more:
Gas laws brainly.com/question/2438000
#learnwithBrainly