Cheyenne live 7/10 miles from school.a fraction in hundredths

What are the solutions to the quadratic equation <img src="https://tex.z-dn.net/?f=x%5E2%20%2B40%3D0" id="TexFormula1" title="x^

Mandarinka [93]

Answer:

In disguise right arrow In Standard Form a, b and c

x2 = 3x − 1 Move all terms to left hand side x2 − 3x + 1 = 0 a=1, b=−3, c=1

2(w2 − 2w) = 5 Expand (undo the brackets),

and move 5 to left 2w2 − 4w − 5 = 0 a=2, b=−4, c=−5

z(z−1) = 3 Expand, and move 3 to left z2 − z − 3 = 0 a=1, b=−1, c=−3

Step-by-step explanation:

sorry it took so long

7 0

3 years ago

Which polynomial can be simplified to a difference of squares

Mrrafil [7]

<h2>Hello!</h2>

The answer is:

The polynomial that can be simplified to a difference of squares is the second polynomial:

$16a^{2}-4a+4a-1=16a^{2}=(4a)^{2}-(1)^{2}=(4-1)(4+1)$

To solve this problem, we need to look for which of the given quadratic terms given for the different polynomials can be a result of squaring (elevating by two).

So,

Discarding, we have:

The quadratic terms of the given polynomials are:

$First=10a^{2}$

$Second=16a^{2}$

$Third=25a^{2}$

$Fourth=24a^{2}$

We have that the coefficients of the quadratic terms that can be obtained by squaring are:

$16a^{2} =(4a)^{2} \\\\25a^{2} =(5a)^{2}$

The other two coefficients are not perfect squares since they can not be obtained by square rooting whole numbers.

So, the first and the fourth polynomial are discarded and cannot be simplified to a difference of squares at least using whole numbers.

Therefore, we need to work with the second and the third polynomial.

For the second polynomial, we have:

$16a^{2} -4a+4a-1=16a^{2}=(4a)^{2}-(1)^{2} =(4-1)(4+1)$

So, the second polynomial can be simplified to a difference of squares.

For the third polynomial, we have:

$25a^{2} +6a-6a+36=16a^{2}+36=(5a)^{2}+(6)^{2}$

So, the third polynomial cannot be simplified to a difference of squares since it's a sum of squares.

Hence, the polynomial that can be simplified to a difference of squares is the second polynomial:

$16a^{2}-4a+4a-1=16a^{2}=(4a)^{2}-(1)^{2}$

7 0

3 years ago

Read 2 more answers

You work 48 hours and 15 minutes. You are paid $13.25 per hour. You earn time

aleksandrvk [35]

Answer: $689.04

Step-by-step explanation:

6 0

2 years ago

¿Como se realizan ecuaciones de primer grado?

Law Incorporation [45]

5^0=1

Any exponent to zero power equals 1

7 0

3 years ago

I don’t understand constant rates of change help!

REY [17]

Answer:

The (constant) rate of change with respect to the variable x of a linear function y = f(x) is the slope of its graph. If x and f have units in Definition 2, then the units of the rate of change are those of f divided by those of x.

Step-by-step explanation:

5 0

3 years ago