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shtirl [24]
3 years ago
13

Which of the following conditions remain constant in Gay-Lussac's law? Temperature and number of moles Volume and number of mole

s Density and temperature Volume and pressure
Chemistry
2 answers:
Evgesh-ka [11]3 years ago
7 0

Answer:

Volume and Number of Moles

Explanation:

I hope this helps !! :)

saw5 [17]3 years ago
3 0

Answer:

Volume and number of moles.

Explanation:

  • Gay-Lussac's law was found by Joseph Louis Gay-Lussac in 1808.
  • It states that, for a given mass (no. of moles) and constant volume of an ideal gas, the pressure exerted on the sides of its container is directly proportional to its absolute temperature.

So, no. of moles and V are constant.

P ∝ T,

<em>∴ P1/T1 = P2/T2.</em>

  • So, the right choice is: <em>Volume and number of moles.</em>
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Can someone answer this ASAP?
Eddi Din [679]

Answer:

С. form chains or rings by bonding to itself and other atoms.

Explanation:

Carbon is an element in group 4 of the periodic table with unique bonding properties. Carbon posseses 4 valence electrons in its outer shell. This enables carbon to form covalent bonds with the atoms of other elements e.g. nitrogen, phosphorus, oxygen, hydrogen etc.

Carbon can also combine covalently with other carbon atoms i.e. C-C to form long chains and rings in a process called CATENATION. This unique property of carbon makes it the only element that can form so many different compounds.

5 0
2 years ago
What is the molarity of 62grams of ammonium in 5liters of water?
Viefleur [7K]

Answer:

Explanation:

First we need to find how many moles of ammonium weigh 62 grams.

Molar mass of NH4 = (14.0)+(4*1.0) grams

or 18.0 grams/mole

62 (g)/18(g/mole) = 3.444... moles of NH4

If it is dissolved in 5 litres of water, the concentration will be 3.444moles/5L

or 0.6888 M.

7 0
3 years ago
A chemistry student is given the task of analyzing the three unknown samples in the previous question. Compare the densities fro
OLEGan [10]

Answer:

It’s B

Explanation:

6 0
2 years ago
PLEASE HELP ASAP PLEASE
USPshnik [31]

Answer:

<em>If it served you, give me 5 stars please, thank you!</em>

<em />

<em>m = </em><u><em>25</em></u><em> </em><em> </em><u><em>Kg</em></u>

8 0
3 years ago
A 1.000 gram sample of an alcohol was burned in oxygen to produce 1.913 g of CO2 and 1.174 g of H20. The alcohol contained only
ycow [4]
The formula of alcohol are
1.913 g CO2/44 = 0.043 moles of CO2*12 = 0.043 moles of C 1.174 gram H2O/18 = 0.065 moles of H.
O: 1 - 0.516 g C - 13 g H = 0.354 g O/16 = 0.022 moles of O.
we have 0.043:0.130.;0.022 as C:H:O. Diving by the smallest no. 0.022 we get 1.95:5.9:1 or 2:6:1 as C:H:O.

hope this help 
4 0
3 years ago
Read 2 more answers
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