if a gas is held in 3.60 L, 298 K AND 800. mmHg, what is the new pressure of the gas if the volume us decreased by half and the

Question

2 years ago

15

tempature is decreased to 250. K

2 answers:

sleet_krkn [62] · Answer 1 · 2022-10-01T02:07:02+03:00

6 0

Answer:

Explanation:

By Ideal Gas Law, P1*V1 / T1 = P2*V2 / T2

So new pressure = (P1*V1 / T1) / (V2 / T2)

= P1*V1*T2 / T1*V2

= 800*3.6*298 / 250*1.8

= 1907.2 mmHg

AlexFokin [52] · Answer 2 · 2022-10-01T03:07:13+03:00

6 0

Apply combine gas law

$\\ \rm\Rrightarrow \dfrac{P1V1}{T1}=\dfrac{P2V2}{T2}$

$\\ \rm\Rrightarrow P2=\dfrac{P1V1T2}{V2T1}$

$\\ \rm\Rrightarrow P2=\dfrac{800(3.6)(250)}{1.8(298)}$

$\\ \rm\Rrightarrow P2=720000/536.4$

$\\ \rm\Rrightarrow P2=1341.7 mmHg$