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Alexandra [31]
2 years ago
7

PLEASE HELP ILL GIVE BRAINLIST. PLEASE TRYPE WHAT TO SAY IN THE QUESTION!!! PLEASE AND THANK YOU!

Mathematics
2 answers:
inysia [295]2 years ago
8 0

Answer:

Using PEMDAS you would multiple first

Step-by-step explanation:

parenthesis ( )

exponent ^#

multiply *

divide /

addition +

subtract -

Alla [95]2 years ago
3 0

Answer:

Step-by-step explanation:

  1. You should Multiply first, because the question says “20 minus the product of” this means that you have to multiply 2 and 5 because whatever 2×5 equals is the product.
You might be interested in
Find the exact values of a) sec of theta b)tan of theta if cos of theta= -4/5 and sin<0
Gre4nikov [31]

Answer:

Using trigonometric ratio:

\sec \theta = \frac{1}{\cos \theta}

\tan \theta = \frac{\sin \theta}{\cos \theta}

From the given statement:

\cos \theta = -\frac{4}{5} and sin < 0

⇒\theta lies in the 3rd quadrant.

then;

\sec \theta = \frac{1}{-\frac{4}{5}} = -\frac{5}{4}

Using trigonometry identities:

\sin \theta = \pm \sqrt{1-\cos^2 \theta}

Substitute the given values we have;

\sin \theta = \pm\sqrt{1-(\frac{-4}{5})^2 } =\pm\sqrt{1-\frac{16}{25}} =\pm\sqrt{\frac{25-16}{25}} =\pm \sqrt{\frac{9}{25} } = \pm\frac{3}{5}

Since, sin < 0

⇒\sin \theta = -\frac{3}{5}

now, find \tan \theta:

\tan \theta = \frac{\sin \theta}{\cos \theta}

Substitute the given values we have;

\tan \theta = \frac{-\frac{3}{5} }{-\frac{4}{5} } = \frac{3}{5}\times \frac{5}{4} = \frac{3}{4}

Therefore, the exact value of:

(a)

\sec \theta =-\frac{5}{4}

(b)

\tan \theta= \frac{3}{4}

7 0
3 years ago
Need help just with number 2 please and thank you!!
BaLLatris [955]
I believe the answer is 17
4 0
3 years ago
In circle A, ∠BAE ≅ ∠DAE. What is the length of BE? 14 units 17 units 27 units 34 units
zhannawk [14.2K]

Answer:

The length of BE is 27 units ⇒ 3rd answer

Step-by-step explanation:

In circle A:

∠BAE ≅ ∠DAE

Line segments A B, A E, and A D are radii

Lines are drawn from point B to point E and from point E to point D to form secants B E and E D

The length of B E is 3 x minus 24 and the length of E D is x + 10

We need to find the length of BE

∵ AB and AD are radii in circle A

∴ AB ≅ AD

In Δs EAB and EAD

∵ ∠BAE ≅ ∠DAE ⇒ given

∵ AB = AD ⇒ proved

∵ EA = EA ⇒ common side in the two triangles

- Two triangles have two corresponding sides equal and the

  including angles between them are equal, then the two

  triangles are congruent by SAS postulate of congruence

∴ Δ EAB ≅ Δ EAD ⇒ SAS postulate of congruence

By using the result of congruence

∴ EB ≅ ED

∵ EB = 3 x - 24

∵ ED = x + 10

- Equate the two expressions to find x

∴ 3 x - 24 = x + 10

- Add 24 to both sides

∴ 3 x = x + 34

- Subtract x from both sides

∴ 2 x = 34

- Divide both sides by 2

∴ x = 17

Substitute the value of x in the expression of the length of BE to find its length

∵ BE = 3 x - 24

∵ x = 17

∴ BE = 3(17) - 24

∴ BE = 51 - 24

∴ BE = 27

The length of BE is 27 units

3 0
3 years ago
Read 2 more answers
I need help solving this, it has 2 parts.
Ratling [72]

Answer:

the part of second is 4second p

6 0
3 years ago
Five friends are going bowling two of the rent shoes at three dollars per pair the group spent $15 at the snack bar the total co
Vedmedyk [2.9K]
66-(3*2)
 60/5= 11
so 11$ for the three who didn't rent shoes and the two who did spent  14 each
8 0
2 years ago
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