Yes
The rule to check if a triplet of numbers can represent the sides of a triangle is the following: the sum of the length of two sides must exceed the third one.
This happens for all possible couples in your case:
When we multiply two negative numbers, one always gets a positive number.
(-)×(-)= +
Hope it helps
31 is a prime number so none
Answer:
look at explanation (I go down the first column of scenarios and then move on to the right column)
Step-by-step explanation:
1) The first one will be same as original because the decrease and increase are the same, and happen right after each other so you get the same amount
2) Second one you get greater than original. You're doubling the initial value, and then decreasing by a smaller percentage, so you still get greater than your initial value
3) Third you get greater than original. You're adding 50% of the initial value, and decreasing by 33.5% of the new value, which will still give you more than the original
4) Fourth, you get greater than original. You're adding 60% of the initial value, and then decreasing by 40% of the new value, which will still give you greater than the initial value
5) Fifth you get less than the original. You're decreasing by 75%, and then adding 50% of the new value, which still gives you less than the initial value
Use the Pythagorean theorem:
x^2 + 6^2 = √117 ^2
x^2 + 36 = √117 ^2
Simplify"
x^2 + 36 = 117
Subtract 36 from both sides:
x^2 = 81
Square both sides:
X = 9
