Answer:
1) Time interval Blue Car Red Car
0 - 2 s Constant Velocity Increasing Velocity
2 - 3 s Constant Velocity Constant Velocity
3 - 5 s Constant Velocity Increasing Velocity
5 - 6 s Constant Velocity Decreasing Velocity
2) For Red and Blue car y₂ = 120 v = = = 20 m/s
We get the same velocity for two cars because it is the average velocity of the car at the given interval of time. It is measured for initial and final position.
3) At t = 2s, the cars are the same position, and are moving at the same rate
Position - same
Velocity - same
The position-time graph shares the same spot for two cars.
Answer:
a)0.22 m/s².
Explanation:
Given that
Net force ,F= 6.8 N
mass ,m = 31 kg
From the second law of Newton's
F = m a ---------------1
Where
F=Net force ,m=mass
a=Acceleration
Now by putting the values in the equation 1
F = m a
6.8 = 31 x a
Therefore the acceleration of the scooter will be 0.22 m/s².
The answer will be "a".
a)0.22 m/s².
Force of a crate : 300 N
<h3>Further explanation</h3>
Given
0.25 meters wide and 1.5 meters long
Pressure = 800 Pa
Required
Force
Solution
P = F/A
A = 0.25 x 1.5
A = 0.375 m²
P = 800 Pa = 800 N/m²
Input the value :
F = P x A
F = 800 N/m² x 0.375 m²
F = 300 N
Your answer is cod!!!
Hope this helped!!
~xox Melis