Answer: the second bullet and the first bullet will both have equal amount of impulse m(V - u) = m(0 - u) = -mu
Explanation: impulse is the change of momentum or the products of force and time.
Ft = m(v-u) = impulse.
Both bullets posses equal amount of force, both bullets will experience equal impulse in coming to rest since they posses equal mass and their initial and final velocities are u and V respectively.
V = 0 sinice they both come to rest.
Ft = m(0 - u) = -mu,
The -ve sign indicates it is towards the direction opposite the direction of motion.
The bullet that penetrates the plate will come to rest faster compared to the bullet that penetrates the layer of clothes.
This means the bullet that penetrates the cloth spends a longer time before coming to rest and hence meets a lesser resistant force compared to the bullet that penetrates the block.
Then the speed of the rider is, v = 2m/s
The linear velocity of an object in a straight line is its speed.
The following is the relationship between linear and angular velocity:
v = rω
The circumference of the bicycle wheel is,
2r = 2
r = 0.318m
The angular velocity of the wheel is,
ω = 1rev/sec = 2rad/s
Then the speed of the rider is,
v = rω
v = 0.318×2π
v = 2m/s
Learn more about angular velocity here:
brainly.com/question/12446100
#SPJ4
Answer:
Explanation:
A.the direction of induced current will be clockwise
B: Changing 18cm and 6.8cm into 0.18m and 0.68
2.5
Divide them both by 2 to find the radius . Now we have 0.09 and .034m.
Now use Φ=(π*0.09^2)(.75 T)cos0 and the 0.019wb
(π*0.034^2)(.75 T)cos0 and the 0.00272wb
ow use ε=-N(ΔΦ/Δt)
For ΔΦ, 0.091-0.0027=0.0883
C.
To find the current, use I=ε/R
0.0883/2.5= 0.035A
The diameter of the sphere is 7.5 cm, therefore its volume is
V = [(4π)/3]*(7.5/2 cm)³ = 220.8932 cm³
The density of the lead ball is 11.34 g/cm³, therefore its mass is
m = (220.8932 cm³)*(11.34 g/cm³) = 2.5049 x 10³ g = 2.5048 kg
Answer: 2.5 kg (nearest tenth)
Resistance of a wire is directly proportional to its length and inversely proportional to the square of its radius.
Thus, if the length is doubled, and the radius is halved:
R₂ = 2R₁/(1/2)²
R₂ = 8R₁
Therefore the resistance increases eight times.