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3 years ago

1. What are the 3 spheres of Earth?

Physics

1 answer:

dolphi86 [110]3 years ago

8 0

they are the lithosphere (land), hydrosphere (water), biosphere (living things), and atmosphere (air).

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I really need help !!

Marat540 [252]

Answer:

The generator will work only if the magnetic field associated with the turns of coil change.

here both magnet and coil are stationary with respect to each other so no electromagnetic induction would take place. so no indiced current will be produced.

the student has to introduce some mechanism either to rotate the coil or the magnet

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3 years ago

A 3.00-kg pendulum is 28.84 m long. what is its period on earth?

GrogVix [38]

$T=2 \pi \sqrt{ \frac{l}{g} }$
This is the period of a pendulum. Notice the mass doesn't matter. Plugging in your values and 9.81m/s^2 for g, gives
T=10.7731s.

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4 years ago

What is a string theory ?

Serggg [28]

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3 years ago

Read 2 more answers

The water-ice particles forming Saturn's rings are frozen together into a thin sheet that rotates around Saturn like a solid bod

vaieri [72.5K]

Answer:

B. False

Explanation:

According to research by several scientists, Saturn's rings aren't solid, as they appear from Earth. They are actually made up of floating chunks of water ice, rocks and dust that range in diferent sizes from specks to enormous, even house-sized pieces that orbit Saturn in a ring pattern.

4 0

3 years ago

An electron with speed 2.45 x 10^7 m/s is traveling parallel to a uniform electric field of magnitude 1.18 x 10^4N/C . How much

cupoosta [38]

Answer:

time will elapse before it return to its staring point is 23.6 ns

Explanation:

given data

speed u = 2.45 × $10^{7}$ m/s

uniform electric field E = 1.18 × $10^{4}$ N/C

to find out

How much time will elapse before it returns to its starting point

solution

we find acceleration first by electrostatic force that is

F = Eq

here

F = ma by newton law

ma = Eq

here m is mass , a is acceleration and E is uniform electric field and q is charge of electron

put here all value

9.11 × $10^{-31}$ kg ×a = 1.18 × $10^{4}$ × 1.602 × $10^{-19}$

a = 20.75 × $10^{14}$ m/s²

so acceleration is 20.75 × $10^{14}$ m/s²

and

time required by electron before come rest is

use equation of motion

v = u + at

here v is zero and u is speed given and t is time so put all value

2.45 × $10^{7}$ = 0 + 20.75 × $10^{14}$ (t)

t = 11.80 × $10^{-9}$ s

so time will elapse before it return to its staring point is

time = 2t

time = 2 ×11.80 × $10^{-9}$

time is 23.6 × $10^{-9}$ s

time will elapse before it return to its staring point is 23.6 ns

7 0

3 years ago