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____ [38]
3 years ago
14

Suppose a fast-pitch softball player does a windmill pitch, moving her hand through a circular arc with her arm straight. She re

leases the ball at a speed of 25.5 m/s (about 57.0 mph ). Just before the ball leaves her hand, the ball's radial acceleration is 1060 m/s2 . What is the length of her arm from the pivot point at her shoulder
Physics
1 answer:
RideAnS [48]3 years ago
4 0

Answer:

61.3 cm

Explanation:

Radial acceleration of the object in circular motion is given by formula

a = \frac{v^2}{R}\\

Given:

a = 1060 m/s^2\\v = 25.5 m/s

 

Plugging in the values in the formula

1060 = \frac{25.5^2}{R}\\R = 0.613 m

so length of his arm is 61.3 cm

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