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djverab [1.8K]
3 years ago
13

Long Snorkel: Inhalation of a breath occurs when the muscles surrounding the human lungs move to increase the volume of the lung

s, thereby reducing the air pressure in the lungs. The difference between the reduced pressure in the lungs and outside atmospheric pressure causes a flow of air into the lungs. The maximum reduction in air pressure that muscles of the chest can produce in the lungs against the surrounding air pressure on the chest and body is about 3740 Pa. Consider the longest snorkel that a human can operate. The minimum pressure difference needed to take in a breath is about 188 Pa. Find the depth h that a person could swim to and still breathe with this snorkel
Physics
1 answer:
Mila [183]3 years ago
4 0

Answer:

h = 0.362 m

Explanation:

The pressure equation with depth is

      P₂ = P_{atm} +ρ g h

The gauge pressure is

       P2 -  P_{atm} = ρ g h

This is the pressure that muscles can create

       P₂ -  P_{atm}= 3740 Pa

But still the person needs a small pressure for the transfer of gases, so

      P₂ -  P_{atm} = 3740 - 188 = 3552 Pa

This is the maximum pressure difference, where the person can still breathe,

Let's clear the height

      h = 3552 / ρ g

      h = 3552 / (1000 9.8)

      h = 0.362 m

This is the maximum depth where the person can still breathe normally.

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An Empty Tank Is Slowly Filled With Air. Water Is Then Added To The Tank, Decreasing The Volume For The Air In The Tank. The Temperature Remains Constant

Explanation:

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3 years ago
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Answer:

x = - 1.4

Explanation:

-5=10x+2-5x     (subtract 5x from both sides)

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-7=5x      (simplify)

x=-7/5     (divide both sides by 5)

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Light incident upon a pane of glass slows down in passing through the glass, Does it emerge at a slower speed or at its initial
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4 0
3 years ago
A playground merry-go-round has a radius of 4.6 m and a moment of inertia of 200 kg-m2 and turns with negligible friction about
tankabanditka [31]

Answer:

8050 J

Explanation:

Given:

r = 4.6 m

I = 200 kg m²

F = 26.0 N

t = 15.0 s

First, find the angular acceleration.

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Fr = Iα

α = Fr / I

α = (26.0 N) (4.6 m) / (200 kg m²)

α = 0.598 rad/s²

Now you can find the final angular velocity, then use that to find the rotational energy:

ω = αt

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ω = 8.97 rad/s

W = ½ I ω²

W = ½ (200 kg m²) (8.97 rad/s)²

W = 8050 J

Or you can find the angular displacement and find the work done that way:

θ = θ₀ + ω₀ t + ½ αt²

θ = ½ (0.598 rad/s²) (15.0 s)²

θ = 67.3 rad

W = τθ

W = Frθ

W = (26.0 N) (4.6 m) (67.3 rad)

W = 8050 J

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3 years ago
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