Answer: (a) and (b) => check attached file.
(c). Picture (a) and (b) will both remain the same.
Explanation:
IMPORTANT: The solution to the question (a) and (b) that is (a) Draw a neat snapshot mode labeled vector picture of the wave. (b) Draw a neat movie mode labeled vector picture of the wave is there in the ATTACHED FILE/PICTURE.
It is also worthy of note to know that in anything Electromagnetic wave, the magnetic field, the Electric Field and their direction of propagation are perpendicular to each other.
Therefore, knowing the fact above we can say that in yellow light, the magnetic field is in the y-direction and the Electric Field is in the z-direction.
Hence, the solution to option C is given below;
(C).If the wave were to represent blue light instead of yellow light, picture (a) will remain the same because both light are Electromagnetic wave, although the wavelength will have to change. Picture (b) will also remain the same because they are both Electromagnetic waves and possess similar properties.
Answer:
38.87 m/s
Explanation:
Given that the ball is dropped from a height = 77 m
u = 0 m/s
s = 77 m
a = g = 9.81 m/s²
Applying the expression as:
Applying values as:
<u>The speed with which the ball hit the ground = 38.87 m/s</u>
Oceanic because it’s denser
<span> <span>We will need to work with the components of the velocity, in the x and the y direction. We will say up is positive so g is -9.81 m/s^2.
Given that the angle was 32 degrees:
Velocity up (in the y direction) is 55 m/s * sin 32 = 29.15 m/s
And
Velocity forward (in the x direction) is 55 m/s * cos 32 = 46.64 m/s
The acceleration of gravity, -9.81 m/s2 continuously decreases the velocity in the y direction. At the maximum height, the velocity will be zero. This should make sense, for as soon as the decreasing velocity becomes negative, the arrow will start to fall.
We have v = v(0) + at
And we set this to zero and solve for t:
0 = 29.15 + -9.81t
9.81t = 29.15
t = 2.97 seconds
To calculate height at this point, we use the equation that calculates position based on time, acceleration, and initial velocity (we could use an alternate too, an equation derived from the one we are now using and v = v(0) + at.
x = x(0) + v(0)t + (1/2)at^2
x = 0 + 29.15 * 2.97 + 0.5 9.81 (2.97)^2
x = 43.30 m
For a projectile, the plot of distance traveled in the upward direction is a parabola, and it takes the same amount of time to come down as it did to go up.
We can double 2.97 to get the time of impact on the target at 2(2.97) = 5.94 seconds
(Alternately, if you like, you can solve
0 = 0 + 29.15t + 0.5 9.81 t^2
And find that the two roots are 0 and 5.94).
http://www.math.com/students/calculators... will do the quadratic for you.
Given a horizontal velocity of 46.64 m/s, we can calculate
46.64 m/s (5.94 s) = 277 m for the distance of the target.</span></span>
