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gayaneshka [121]
3 years ago
7

How do you find the net force when two forces act in opposite directions

Physics
1 answer:
blagie [28]3 years ago
5 0
If two for the acts on an object in opposite directions and they don't exactly cancel, what is left over is the net force (the difference in the forces). In the diagram at left, the net force is 2 Newtons to the right. If two(or more) forces act on an object in the same direction, the net force is the sum of the forces.

Thank for choosing brainly

Please choose brainliest
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A train of mass 5.6 × 10^5kg is at rest in a station.at time t=0s, a resultant force acts on the train and it starts to accelera
lana66690 [7]

Answer:

420000N

Explanation:

Given parameters:

Mass of the train  = 5.6 x 10⁵kg

Acceleration  = 0.75m/s²

Unknown:

Resultant force = ?

Solution:

According to newton's second law, force is the product of mass and acceleration;

   Force  = mass x acceleration

Resultant force that acts on the train is given below;

 Force  = 5.6 x 10⁵kg  x 0.75m/s²  = 420000N

7 0
3 years ago
A battery sits in an iPod before the iPod is turned on.
Stells [14]
I believe the answer is electric
5 0
3 years ago
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As a ball is released from 10ft above the ground, it falls freely (without friction)
Masteriza [31]

Answer:

Explanation:

The formula to find Potential Energy is PE = mgh, where m is the mass of the object, g is gravity, and h is the height from which the object can potentially fall. Because this is linear, then PE will increase as either the mass or the height increase (gravity is constant at 9.8 m/s/s). If the mass of the ball being dropped doesn't change, then the only thing that determines this ball's max PE is the height from which it is dropped; max PE ALWAYS occurs at the highest point from which an object can potentially fall. So your answer is "At the top".

7 0
3 years ago
a driver travels 135 km, east in 1.5 h, stops for 45 minutes for lunch, and then resumes driving for the next 2.0 h through a di
daser333 [38]

Answer:

v = 98.75 km/h

Explanation:

Given,

The distance driver travels towards the east, d₁ = 135 km

The time period of the travel, t₁ = 1.5 h

The halting time, tₓ = 46 minutes

The distance driver travels towards the east, d₂ = 215 km

The time period of the travel, t₁ = 2 h

The average speed of the vehicle before stopping

                                    v₁ = d₁/t₁

                                        = 135/1.5

                                       = 90 km/h

The average speed of vehicle after stopping

                                    v₂ = d₂/t₂

                                         = 215/2

                                        = 107.5 km/h

The total average velocity of the driver

                                      v = (v₁ +v₂) /2

                                         = (90 + 107.5)/2

                                         = 98.75 km/h

Hence, the average velocity of the driver, v = 98.75 km/h

7 0
4 years ago
NO LINKS PLEASE; On the calendar, the full moon is shown happening on the eleventh of the month. What moon would you see around
photoshop1234 [79]

Wanning gibbous

hope it helps u

<em>Plz </em><em>mrk </em><em>me </em><em>brainlest</em>

3 0
3 years ago
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