A train of mass 5.6 × 10^5kg is at rest in a station.at time t=0s, a resultant force acts on the train and it starts to accelera
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#2
speed of bird = 31 m/s
time = 13 s
since here bird maintains its speed to be constant
so here the distance traveled is given by
so bird will travel 403 m distance while maintaining its speed to be constant
#3
average speed is the ratio of total distance covered and total time
here Ian walk 2 km then 0.5 km and then 2.5 km so the total distance is given as
total time of his full motion is
so the average speed of the motion is
so here average speed of Ian is 1.67 km/h
#4
Initial speed of the truck is 6 m/s
after 4 s interval of time
final speed of the truck is 14 m/s
so the acceleration is rate of change in velocity
so it is given as
so here truck accelerated with 2 m/s^2
#5
Here car starts from rest so its initial speed is 0
after 2.5 s interval of time
final speed of the car is 15 m/s
so the acceleration is rate of change in velocity
so it is given as
so here car accelerated with 6 m/s^2
#6
a bag full of trash is dropped from the balcony
Here we can say when bag is in air
the net force on the bag is only due to its weight
so here we can use Newton's II law to find the acceleration of bag
so here bag will have constant acceleration during its whole motion as we can see that there is no change in the force and hence its acceleration always remains constant