All categories

2 years ago

Find the volume of a rectangular prism with the dimensions:

Mathematics

2 answers:

larisa86 [58]2 years ago

8 0

Answer:

220

Step-by-step explanation:

V= whl = 5 · 11 · 4 = 220

Cerrena [4.2K]2 years ago

4 0

<h2><u>Question</u>:-</h2>

Find the volume of a rectangular prism with the dimensions:

length: 4 yd

width: 5 ft

height: 11 ft

<h3>Given:-</h3>

$\bullet$ Length of a rectangular prism = 4 yards = 4 × 3 = 12 feet.

$\bullet$ Breadth of a rectangular prism = 5 feet.

$\bullet$ Height of a rectangular prism = 11 feet.

The volume of a rectangular prism.

<h2>Solution:-</h2>

We know,

Formula of Volume of a rectangular prism is (Length × Breadth × Height) cubic units.

So, Volume = (12 × 5 × 11) cubic feet

Volume = 660 cubic feet

<h3>The volume of a rectangular prism is <u>6</u><u>6</u><u>0</u><u> </u><u>cubic </u><u>f</u><u>e</u><u>e</u><u>t</u>. [Answer]</h3>

You might be interested in

A bucket full of milk is 80cl,how many litres are in 15 of such

PIT_PIT [208]

Answer:

1.2 liters

Step-by-step explanation:

1 bucket has a volume of 80 cL.

15 buckets have a volume of 15 * 80 cL = 120 cL

1 L = 100 cL

120 cL * (1 L)/(100 cL) = 1.2 L

5 0

3 years ago

Below is a pair of vectors. add them and insert your answer here: ab+bc=(-3-1)+(-4 2)=<br>

jarptica [38.1K]

Answer:

(-7, 1)

Step-by-step explanation:

Add the x and y values separately which is across from your screen to get the function which is (-7, 1).

8 0

2 years ago

What is the equivalent fraction of 84/120?

Zigmanuir [339]

84/120 can be reduced to 7/10

7 0

3 years ago

Find X.............

Mrrafil [7]

Your answer is x = 78! Hope this helps!

3 0

3 years ago

2. The quality assurance department inspects its production line. The product either fails or passes the inspection. Past experi

Oksana_A [137]

Answer:

(a) $E(X) = 950$

(b) $COV = 0.007255$

Step-by-step explanation:

The given problem can be solved using binomial distribution since the product either fails or passes, the probability of failure or success is fixed and there are n repeated trials.

probability of failure = q = 0.05

probability of success = p = 1 - 0.05 = 0.95

number of trials = n = 1000

(a) What is the expected number of non-defective units?

The expected number of non-defective units is given by

$E(X) = n \times p \\\\E(X) = 1000 \times 0.95 \\\\E(X) = 950$

(b) what is the COV of the number of non-defective units?

The coefficient of variance is given by

$COV = \frac{\sigma}{E(X)}$

Where the standard deviation is given by

$\sigma = \sqrt{n \times p\times q} \\\\\sigma = \sqrt{1000 \times 0.95\times 0.05} \\\\\sigma = 6.892$

So the coefficient of variance is

$COV = \frac{6.892}{950}$

$COV = 0.007255$

(c) What is the probability of having more than 980 non-defective units?

We can use the Normal distribution as an approximation to the Binomial distribution since n is quite large and so is p.

$P(X > 980) = 1 - P(X < 980)\\\\P(X > 980) = 1 - P(Z < \frac{x - \mu}{\sigma} )\\\\$

We need to consider the continuity correction factor whenever we use continuous probability distribution (Normal distribution) to approximate discrete probability distribution (Binomial distribution).

$P(X > 980) = 1 - P(Z < \frac{979.5 - 950}{6.892} )\\\\P(X > 980) = 1 - P(Z < \frac{29.5}{6.892} )\\\\P(X > 980) = 1 - P(Z < 4.28)\\\\$

The z-score corresponding to 4.28 is 0.99999

$P(X > 980) = 1 - 0.99999\\\\P(X > 980) = 0.00001\\\\$

So it means that it is very unlikely that there will be more than 980 non-defective units.

8 0

3 years ago