Which point keeps the set of ordered pairs a function {(1,-2).(-2,4), (5,0)}
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Answer:
Step-by-step explanation:
For the function to have a domain of all reals, the denominator cannot have a value of zero. x^2 + 2cx + 14 will not have zero as a root if it has no real solutions. A quadratic equation has no solutions when the discriminant is negative.
b^2 - 4ac < 0
(2c)^2 - 4(1)(14) < 0
4c^2 - 56 < 0
4c^2 < 56
c^2 < 14