There are 600 students including the seventh and eighth graders at the party.
This problem uses the concept of percentages to define the conditions that are laid in front of us.
Let the original number of students be S , and the number of seventh graders be = 0.60S
We know that percent is used to convey the mathematical term of a fraction multiplied by 100.
Total students after 20 eighth graders arrive = S + 20
And we have that
Number of seventh graders / total number of students = 58%
.60S / [ S + 20 ] = .58 we multiply both sides by S + 20
0.60S =0 .58 [ S + 20]
.60S = .58S + 11.6 we subtract 0.58S from both the sides
0.02S = 11.6 we divide both the sides by .02
S = 11/6 / 0.02 = 580
So the total number of students = 580 + 20 = 600 .
Hence there are 600 students at the party at that time.
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10 cents, cause the {ball +$1.00=$1.10} subtract $1 from both sides the ball=$0.10
All we have to do is replace n with 4.
-6-4(4-1)
Parenthesis first.
-6-4×3
Multiplication next.
-6-12
Now subtract.
-18
The 4th term is -18.
Tell me if this helps!!
Answer:
x ≤ 3764.72
Step-by-step expl
anation:
The Montanez family cannot use more than 7250.50 gallons, this means that they can use less than or equal to 7250.50 gallons, this tells you which sign to use. The variable x can be used to describe how much water they have left to use and then you add 3,485.78 gallons to x.
x + 3485.78 ≤ 7250.50 This inequality means that the amount of water the family has yet to use added to 3485.78 gallons cannot exceed 7250.50 gallons.
Next, you simplify the inequality using the property of inequalities.
x ≤ 7250.50 - 3485.78
x ≤ 3764.72
Answer:
1.4
Step-by-step explanation:
