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REY [17]
4 years ago
9

15 Points and brainliest!

Biology
2 answers:
TiliK225 [7]4 years ago
5 0

An acid donates hydrogen ions to a solution, but a base accepts hydrogen ions.

inna [77]4 years ago
4 0

acid

and base

are the correct answer respectively

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Which of these is formed when a potassium ion is attracted to a chloride ion?
hoa [83]

Answer:

OD.

Explanation:

BECAUSE THE BOND WAS IONIC AND IT'S FORMING A COMPOUND OF ELEMENTS SORRY 4 THE CAPS LOCK THE BUTTON'S JAMMED

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3 years ago
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Oxygen is very electronegative and therefore is a strong reducing agent
Roman55 [17]

The oxygen atoms undergo reduction, formally gaining electrons, while the carbon atoms undergo oxidation, losing electrons. Thus oxygen is the oxidizing agent and carbon is the reducing agent in this reaction.

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3 years ago
How do you think this transfer of electrons helps the lactic acid fermentation process repeat itself?
Lisa [10]

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By changing pyruvate into lactic acid with this transfer of electrons.

Explanation:

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3 years ago
At a seismic station, s-waves arrive first, followed by p-waves second.
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Actually, it is false. P-waves arrive first and then S-waves arrive.
6 0
3 years ago
Suppose a population grows according to a logistic model with initial population 500 and carrying capacity 5,000. If the populat
Gre4nikov [31]

Answer:

4,500

Explanation:

The logistic growth model is given by:

\frac{dP}{dt}=rP(1-\frac{P}{K} )

Solving for P(t), we obtain:

P(t)=\dfrac{KP_0e^{rt}}{(K-P_0)+P_0e^{rt}}$ where:\\P_0=$Initial Population\\K=Carrying Capacity\\r=Growth rate\\P(t)=Population at a time t.

We are given that:

I$nitial Population,P_0=500\\$Carrying Capacity,K=5000\\Population after one year, P(1)=1250 \implies t=1

Therefore:

1250=\dfrac{500 \times 5000e^{r \times 1}}{(5000-500)+500e^{r\times 1}}\\\\1250[(5000-500)+500e^{r}]=500 \times 5000e^{r}\\4500+500e^{r}=2000e^{r}\\2000e^{r}-500e^{r}=4500\\1500e^{r}=4500\\e^r=3\\$Take the natural logarithm of both sides\\r =\ln 3

We want to determine the population after another three years. i,e When t=4

P(4)=\dfrac{500 \times 5000e^{\ln|3| \times 4}}{(5000-500)+500e^{\ln|3| \times 4}}\\=\dfrac{2,500,000e^{\ln|3| \times 4}}{4500+500e^{\ln|3| \times 4}}\\P(4)=4500

Therefore, after another three years, the population will be 4500.

5 0
3 years ago
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