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3 years ago

What process is used to find technological solutions.

1 answer:

5 0

<span>Step one Define the problem. Step two </span>Generate alternative solutions. Step three Evaluate and select an a. Hope this helped you!<span />

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When the body becomes overheated, how does the body react to maintain homeostasis?

erastovalidia [21]

Answer:

Nervous system directs your body to swear to release heat.

Explanation:

Sweat maintains homeostasis when overheating.

4 0

2 years ago

Exactly 16 mL of a solution A is diluted to 300 mL, resulting in a new solution B that has 0.50 M concentration. If the solution

nordsb [41]

Answer:

8.77g

Explanation:

Step 1:

Data obtained from the question.

This includes the following:

Concentration of A (C1) =.?

Volume of A (V1) = 16 mL

Volume of B (V2) = 300 mL

Concentration of B (C2) = 0.50 M

Molar Mass of NaCl = 58.443 g/mol

Mass of NaCl =.?

Step 2:

Determination of the concentration of A.

Applying the dilution formula:

C1V1 = C2V2

The concentration of A i.e C1 can be obtained as follow:

C1V1 = C2V2

C1 x 16 = 0.5 x 300

Divide both side by 16

C1 = (0.5 x 300) / 16

C1 = 9.375 M

Therefore, the concentration of A is 9.375 M

Step 3:

Determination of the number of mole of NaCl in 9.375 M NaCl solution. This is illustrated below:

Molarity = 9.375 M

Volume = 16 mL = 16/1000 = 0.016 L

Mole of NaCl =?

Molarity = mole /Volume

Mole =Molarity x Volume

Mole of NaCl = 9.375 x 0.016

Mole of NaCl = 0.15 mole

Step 4:

Determination of the mass of NaCl. This is illustrated below:

Mole of NaCl = 0.15 mole

Molar Mass of NaCl = 58.443 g/mol

Mass of NaCl =?

Mass = number of mole x molar Mass

Mass of NaCl = 0.15 x 58.443

Mass of NaCl = 8.77g

Therefore, 8.77g of NaCl is needed to make 1 L of the original solution A.

7 0

3 years ago

Read 2 more answers

An athlete preparing for a marathon runs 21.3 miles. How many kilometers did they run?

densk [106]

Answer: 34.27903 km

Explanation: for an approximate result, multiply the length value by 1.609 to 21.3 to get answer.

8 0

3 years ago

Calculate the number of moles 3.16 g of KMnO4 32.33 g of K2CrO4 100 g of KHCO3

kvasek [131]

The number of moles:
3.16g of $KMnO_{4}$
1 mole of $KMnO_{4}$ - 158g.
x moles of $KMnO_{4}$ - 3.16g.
$x=\frac{1\ mole*3.16g}{158g}=\frac{3.16}{158}=0.02\ mole$

The number of moles:
32.33g of $K_{2}CrO_{4}$
1 mole of $K_{2}CrO_{4}$ - 194g.
x moles of $K_{2}CrO_{4}$ - 32.33g.
$x=\frac{1\ mole*32.33g}{194g}=\frac{32.33}{194}=0.17\ mole$

The number of moles:
100g of $KHCO_{3}$
1 mole of $KHCO_{3}$ - 100.1g.
x moles of $KHCO_{3}$ - 100g.
$x=\frac{1\ mole*100g}{100.1g}=\frac{100}{100.1}=0.999\ mole$

Greetings,
n00nst00p :)

3 0

3 years ago

What period is the atom in?

kupik [55]

- Period 2
- Group 14
- Carbon
- Silicon
- Yes, depending on the allotrope.

6 0

3 years ago