Answer:
Five significant figures.
Explanation:
The given measurement have five significant figures 52301.
All non-zero digits are consider significant figures like 1, 2, 3, 4, 5, 6, 7, 8, 9.
Leading zeros are not consider as a significant figures. e.g. 0.03 in this number only one significant figure present which is 3.
Zero between the non zero digits are consider significant like 104 consist of three significant figures.
The zeros at the right side e.g 2400 are also significant. There are four significant figures are present.
Answer:
2NaHCO3 + H2SO4 -----> Na2SO4 + 2H2O + 2CO2.
Explanation:
Explanation:
We can summarize the reaction shown as:
2F₂ + I₂ → 2F₃I
Since I is purple
F is the green
The number of I atoms in the reactants is greater than the number in the product
False:
The number of I atoms on both side of the expression is 2
There are 4 atoms of F in both the reactants and the products.
False:
There are 4 atoms of F on the reactant side and 6 atoms of F on the product side
The illustration represents a valid chemical transformation. True or false
False
The reaction does not represent a valid chemical transformation because in a valid chemical transformation, the number of atoms on both sides of the expression must be the same.
<span>B. S⁰(s) + 2H⁺ + 2e⁻ –--> H2S⁰(g)
by mass: 1 S and 2 H ----> 2 H and 1S True.
by charge : 0 +(2*(+1)) + 2*(-1) = 0, 0+2-2=0, 0 = 0 True.</span>
