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Irina18 [472]
3 years ago
6

3. You are asked to prepare an aqueous solution. What would be a better choice for a solute potassium nitrate or

Chemistry
1 answer:
liubo4ka [24]3 years ago
8 0

Answer:

i do not knowwww

Explanation:

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Which actions increase the strength of an electromagnet? Question 5 options: Increase the number of coils and decrease the stren
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An electromagnet is a device in which, by electric current, the magnetic field is produced. Increase the number of coils and increase the strength of the current, thus, increasing the strength of an electromagnet.

The correct option is B.

<h3>What is an electromagnet?</h3>

An electromagnet is a device that consists of a magnetic core encircled by a coil, through which an electric current is carried to magnetize the core.

Wherever controllable magnets are required, such as in devices where the magnetic flux must be adjusted, reversed, or switched on and off, an electromagnet is utilized.

Thus, the correct option is B, increasing the number of coils and increasing the strength of the current.

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3 years ago
Wich of the following is a unit of volume in the english system of mesurement​
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Which of the following is true about the mass of atoms?
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4 0
2 years ago
If 2.60 g of NaBr are dissolved in enough water to make 160. mL of solution, what is the molar concentration of
navik [9.2K]

This problem has two parts; the first one asking for the concentration of NaBr given both its mass and volume and the second one asking for its volume given both mass and concentration. The answers turn out to be 0.158 M and 211 mL.

<h3>Molarity</h3>

In chemistry, the use of units of concentration depends on both the substances to analyze and their amounts. In such a way, for molarity, one needs the following relationship between the moles of solute and volume of solution:

M=\frac{n}{V}

Thus, for the first part of the problem we first calculate the moles in 2.60 g of NaBr via its molar mass:

2.60g*\frac{1mol}{102.89g} =0.0253mol

Next, we convert the 160. mL to L by dividing by 1000 in order to obtain 0.160 L to subsequently calculate the molarity:

M=\frac{0.0253mol}{0.160L}=0.158M

Next, since the moles remain the same and for the second part we are asked for the volume given the concentration, one can solve for the volume so as to obtain:

V=\frac{n}{M} =\frac{0.158M}{0.120mol/L}\\ \\V=0.211L

That in milliliters turns out to be:

V=0.211L*\frac{1000mL}{1L}=211mL

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