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algol13
3 years ago
13

Suppose that the quality control manager for a cereal manufacturer wants to ensure that bags of cereal are being filled correctl

y. The equipment is calibrated to fill bags with a mean of 17 oz of cereal with a standard deviation of 0.2 oz. The quality control inspector selects a random sample of 52 boxes and finds that the mean amount of cereal for these boxes is 17.04 oz. He uses this data to conduct a one-sample z ‑test with a null hypothesis of H 0 : μ = 17 against the alternative hypothesis H 1 : μ ≠ 17 , where μ is the mean amount of cereal in each box. He calculates a z ‑score of 1.44 and a P -value of 0.1499 .
Are these results statistically significant at a significance level of 0.05?
No, these results are not statistically significant because p>0.05,
No, these results are not statistically significant because p < 0.05.
Yes, these results are statistically significant because p < 0.05.
Yes, these results are statistically significant because p > 0.05.
Mathematics
1 answer:
likoan [24]3 years ago
6 0

Answer: No, these results are not statistically significant because

p > 0.05

Step-by-step explanation:

The null hypothesis is

H0 : μ = 17

The alternative hypothesis is

H 1 : μ ≠ 17

where μ is the mean amount of cereal in each box.

The p value that he got is 0.1499. This is greater than alpha = 0.05 which is the given level of significance.

If the level of significance is lesser than the p value, we would accept the null hypothesis.

Therefore, the correct option is

No, these results are not statistically significant because p>0.05

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Mable has 185 dollars worth of apples. Each apple is worth more then 3 dollars but less then 10 dollars. The number has four let
velikii [3]

Answer:

The worth of each of Mable's apples is $5

Step-by-step explanation:

 Extracting the key information from the question:

***Mable has apples that are worth a combined 185 dollars.

*** One apple from Mable's apples worth more than three ($3) dollars but less than ten ($10) dollars.

***The cost of one apple is a number that has four letters.

*** That number (the cost) of one apple is also a prime number.

*** We are required to find or determine the worth of one of Mable's apples.

   Now, one of the clues given to us which we may use to figure out the cost or worth of one apple is that the apple is worth more than three dollars ($3) but worth less than ten dollars ($10). This means that each Mable's apple may worth $4 or $5 or $6 or $7 or $8 or $9. That is one of Mable's apples worth from $4 to $9

   Another clue to solving this puzzle is that the worth of one apple in dollars is a prime number. This implies that one of Mable's apples may worth either five dollars ($5) or seven dollars ($7).

   

  The next clue for unravelling this mystery is that all Mable's apples are worth a combined $185. This then means that the worth of each apple (the number) must be able to divide 185.

   Since $7 and $5 are the only two figures left standing, we will then try and see which one of them will be able to do divide the number "185".

 185/7  = 26 remainder 3

 185/5  = 37 remainder 0

 The final clue in the question is that the worth of each of Mable's apples is a figure/number that has only letters:

$7 SEVEN has = 5 letters

$5 FIVE has = 4 letters

 This now brings us to the conclusion that the worth of each of Mable's apples is five dollars ($5)  since it meets all the requirements and clues in the question.

6 0
3 years ago
i a man even number beetween 50 and 99 i am a multiple of 9 my tens digit is 5 more than my units digit
vodomira [7]
Hello,
multiple of 9 betheen 50 and 99 are :54,63,72,81,99
and 54,72  are even.
5-4=1 and not 5
7-2=5 ok

72 is the number searched.
6 0
3 years ago
PLZZZZZZZZZZZ HELP MEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEE!!!!
Digiron [165]
The answer is 51 liters.

Since they have a direct relationship, set up a direct proportion.
17/476=x/1428
476x3 is 1428 so
17x3=51
3 0
3 years ago
Find the range and interquartile range for the data represented by the box plot.
Anarel [89]

<u>Given</u>:

Given that the data are represented by the box plot.

We need to determine the range and interquartile range.

<u>Range:</u>

The range of the data is the difference between the highest and the lowest value in the given set of data.

From the box plot, the highest value is 30 and the lowest value is 15.

Thus, the range of the data is given by

Range = Highest value - Lowest value

Range = 30 - 15 = 15

Thus, the range of the data is 15.

<u>Interquartile range:</u>

The interquartile range is the difference between the ends of the box in the box plot.

Thus, the interquartile range is given by

Interquartile range = 27 - 18 = 9

Thus, the interquartile range is 9.

3 0
3 years ago
Read 2 more answers
A circular garden is enlarged so that the new diameter is twice the old diameter. What is the ratio of the original area to the
Amanda [17]

Answer:

  • Explained briefly below.

Step-by-step explanation:

<u>For old circular garden:</u>

take the radius as r.

then use the formula to find area of circle: πr² ......this is old garden area.

<u>For new enlarged garden:</u>

the radius is twice the old radius so, radius = 2 * r = 2r ......enlarged radius

now find area for this new garden:  π(2r)² → 4πr²

In common fractions: (old garden)/(new garden)

                                : ( πr² ) / ( 4πr² )

                                 :    1/4

7 0
2 years ago
Read 2 more answers
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