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algol13
3 years ago
13

Suppose that the quality control manager for a cereal manufacturer wants to ensure that bags of cereal are being filled correctl

y. The equipment is calibrated to fill bags with a mean of 17 oz of cereal with a standard deviation of 0.2 oz. The quality control inspector selects a random sample of 52 boxes and finds that the mean amount of cereal for these boxes is 17.04 oz. He uses this data to conduct a one-sample z ‑test with a null hypothesis of H 0 : μ = 17 against the alternative hypothesis H 1 : μ ≠ 17 , where μ is the mean amount of cereal in each box. He calculates a z ‑score of 1.44 and a P -value of 0.1499 .
Are these results statistically significant at a significance level of 0.05?
No, these results are not statistically significant because p>0.05,
No, these results are not statistically significant because p < 0.05.
Yes, these results are statistically significant because p < 0.05.
Yes, these results are statistically significant because p > 0.05.
Mathematics
1 answer:
likoan [24]3 years ago
6 0

Answer: No, these results are not statistically significant because

p > 0.05

Step-by-step explanation:

The null hypothesis is

H0 : μ = 17

The alternative hypothesis is

H 1 : μ ≠ 17

where μ is the mean amount of cereal in each box.

The p value that he got is 0.1499. This is greater than alpha = 0.05 which is the given level of significance.

If the level of significance is lesser than the p value, we would accept the null hypothesis.

Therefore, the correct option is

No, these results are not statistically significant because p>0.05

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PLEASE HELP ASAP, I HAVE 10 MINUTES ;
Ilya [14]

Answer:

Step-by-step explanation:

when 13 bought we find these inequalities

x + 12y < 7  no

2x + 11y < 7.5 no

3x + 10y < 8 no

4x + 9y < 8.5 no

5x + 8y >  9  yes

When 14 bought we find these inequalities

x + 13y < 7.5 no

2x + 12y < 8 no

3x + 11y < 8.5 no

4x + 10y > 9 yes  

7 0
3 years ago
What is the measurement of angle POR
IgorLugansk [536]

Let us observe the given figure,

When two lines intersect each other, the angles opposite to each other are Vertically Opposite Angles. Vertically opposite angles are always equal in measure.

As, we can observe that the given lines intersect each other, and they form vertically opposite angles as \angle POR , \angle SOQ and  \angle POS , \angle ROQ

Therefore, \angle POR = \angle SOQ

Substituting the given measures of the angles, we get

91-x^\circ = x+ 7^\circ

91-7 = x + x

84 = 2x

x = \frac{84}{2}

So, x = 42^\circ

Since, the measure of angle POR = (91-x)^\circ

= (91-42)^\circ

= 49^\circ

Therefore, the measure of angle POR is 49 degrees.

8 0
4 years ago
ANswer this question!!!!!
4vir4ik [10]

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6 0
3 years ago
There are 68 apples in the school kitchen. The school needs 130 apples for all the students in grade 2. The school gets two boxe
WITCHER [35]

Answer:No they do not have enough they only have 82 apples

Step-by-step explanation:

7 0
3 years ago
A teacher was interested in knowing the amount of physical activity that his students were engaged in daily. He randomly sampled
klasskru [66]

Answer:

The standard error of the mean is 4.5.

Step-by-step explanation:

As we don't know the standard deviation of the population, we can estimate the standard error of the mean from the standard deviation of the sample as:

\sigma_{\bar{x}}\approx\frac{s}{\sqrt{n}}

The sample is [30mins, 40 mins, 60 mins, 80 mins, 20 mins, 85 mins]. The size of the sample is n=6.

The mean of the sample is:

\bar{x}=\frac{1}n} \sum x_i =\frac{30+40+60+80+20+85}{6}=52.5

The standard deviation of the sample is calculated as:

s=\sqrt{\frac{1}{n-1}\sum (x_i-\bar x)^2} \\\\ s=\sqrt{\frac{1}{5}\cdot ((30-52.5)^2+(40-52.5)^2+(60-52.5)^2+(80-52.5)^2+(20-52.5)^2+(85-52.5)^2}\\\\s=\sqrt{\frac{1}{5} *3587.5}=\sqrt{717.5}=26.8

Then, we can calculate the standard error of the mean as:

\sigma_{\bar{x}}\approx\frac{s}{\sqrt{n}}=\frac{26.8}{6}= 4.5

6 0
3 years ago
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