Answer:
Base of the original triangle is 12 cm.
Step-by-step explanation:
Let base of triangle be x
two equal legs of triangles by y
therefore perimeter of triangle
x+y+y = 50 or x+2y =50
according to the question
if base is x+3 and leg is y-4
then both are equal
that is x+3 = y-4
y-x = 7 or y =x+7
x+2y =50
x+2(x+7) = 50
x+2x +14 =50
3x +14 =50
3x = 50 -14
3x = 36
x = 12
therefore base of the original triangle is 12 cm
When solving system equations, we can use substitution method or elimination. Today I'm using substitution method.
First name the 2 equations.
3x + y = 3 (1)
x + y = 2 (2)
Now pick one equation and express one algebra in forms of the other.
From (2),
x = 2 - y (3)
Now substitute (3) into (1),
3(2-y) + y = 3
6 - 3y + y = 3
6 - 2y = 3
6 - 3 = 2y
y = 1.5
Now substitute y = 1.5 into (2)
x + 1. 5 = 2
x = 2 - 1.5
x = 0.5
Therefore the answer is x = 0.5 and y = 1.5
48 inches is the area in the front of the building
That is the centroid.
The point where the lines from each vertex of the triangle to the midpoints of the opposite sides intersect.
Logarithm properties:
![\displaystyle \log_a b+\log_a c=\log_a (b\cdot c)\\\\\log_ab-\log_a c=\log_a \left( \frac{b}{c} \right)\\\\\log_{a^p}b^q= \frac{q}{p} \log_a b](https://tex.z-dn.net/?f=%5Cdisplaystyle%20%5Clog_a%20b%2B%5Clog_a%20c%3D%5Clog_a%20%28b%5Ccdot%20c%29%5C%5C%5C%5C%5Clog_ab-%5Clog_a%20c%3D%5Clog_a%20%5Cleft%28%20%5Cfrac%7Bb%7D%7Bc%7D%20%5Cright%29%5C%5C%5C%5C%5Clog_%7Ba%5Ep%7Db%5Eq%3D%20%5Cfrac%7Bq%7D%7Bp%7D%20%5Clog_a%20b)
According to this, we can get: