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zloy xaker [14]
2 years ago
7

A female fly, full of fertilized eggs, is swept by high winds to an island far out to sea. she is the first fly to arrive on thi

s island, and the only fly to arrive in this way. thousands of years later, her numerous offspring occupy the island, but none of them resembles her. there are, instead, several species, each of which eats only a certain type of food. none of the species can fly, for their flight wings are absent, and their balancing organs (in other words, halteres) are now used in courtship displays. the male members of each species bear modified halteres that are unique in appearance to their species. females bear vestigial halteres. the ranges of all of the daughter species overlap. if these fly species lost the ability to fly independently of each other as a result of separate mutation events in each lineage, then the flightless condition in these species could be an example of
Biology
1 answer:
FrozenT [24]2 years ago
8 0
Species selection. Species selection is the process by which intrinsic biological characteristics in organisms change depending on the type of environment they're interacting with. In this case, the subsequent generations of the fly lost the ability to fly because their environment didn't require them to use wings for survival, hence they stopped growing them and subsequently lost the ability to fly.
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Part C Firefly luciferase is the enzyme that allows fireflies to illuminate their abdomens. Because this light generation is an
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Answer:

K = 9.620 × 10⁻⁶

Explanation:

From the given information:

Temperature T= 6° C

= (273 + 6)K

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The correct and well presentation of the reactions are:

1. Luciferin + O_2     ⇆     oxyluciferin + light   ΔG₁°

2. ATP                     ⇄   AMP + PP_i                  ΔG₂°  = -31.6 kJ/mol

The overall  ΔG° = -4.80 kJ/mol

Let's first determine the ΔG₁° for the equation (1)

ΔG° = ΔG₁° + ΔG₂°

- ΔG₁° = - ΔG° + ΔG₂°

ΔG₁° = ΔG° - ΔG₂°

ΔG₁° = ( -4.80 - (-31.6) ) kJ/mol

ΔG₁° = 26.8 kJ/mol

Using the formula:

ΔG° = -RTIn K

In \  K =\dfrac{-\Delta G^0}{RT} \\ \\ log \ K = -\dfrac{\Delta G^0}{2.303RT}

log \ K = -\dfrac{\Delta G_1^0}{2.303RT} \\ \\ log \ K = -\dfrac{26.8 \times 10^3 \ J/mol}{2.303\times 8.314 \ J/mol/K \times 279 \ K} \\ \\ log \  K =- 5.017

K = antilog (-5.017)

K = 9.620 × 10⁻⁶

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Explanation:

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