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san4es73 [151]
4 years ago
15

Ricardo can type 39 words per minute. Estimate the number of words he can type in 18 minutes. 400 or 600 or 300 or 800

Mathematics
2 answers:
Free_Kalibri [48]4 years ago
4 0
600 words per minute my guys
Mandarinka [93]4 years ago
3 0

Answer:

800

Step-by-step explanation:

ROund 39 to 40 and 18 to 20.

This results in 40 x 20=800.

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What is the midpoint of the segment shown below?
Nezavi [6.7K]

Answer:

(-9/2,3/2)

Step-by-step explanation:

x coordinate of mid point=(x1+x2)/2

y coordinate of mid point=(y1+y2)/2

4 0
3 years ago
What is the domain of the relation {(2, 8), (0, 8), (–1, 5), (–1, 3), (–2, 3)}?
lesya [120]
(2,0,-1,-1,-2) that is the domain from what I remember. Hope that help
6 0
3 years ago
Read 2 more answers
any help will be helpful and you have to make ur own graph paper if you don't have none he said but please help I don't understa
ivann1987 [24]

Step-by-step explanation:

do you need graph paper?

just minus the 2nd cordnates x to the 1dt cordnates x and same for the y. that will give you the distance for each x and y points

8 0
3 years ago
8th grade geometry part 3, please explain the steps :)))
Illusion [34]

Answer: Volume = 97.6

Step-by-step explanation:

Volume of the cone first

V = 1/3 h π r²

<u>h = 0.7</u>

<u>r = 2</u>

V = 1/3 × 0.7 × 2² × 3.14

V = 1/3 × 0.7 × 4 × 3.14

V = 1/3 × 8.792

V = 2.93

Then find the volume of the cylinder if the cone was there.

V = π r² h

<u>r = 2</u>

<u>h = 8 </u>

V = 3.14 × 2² × 8

V = 3.14 × 4 × 8

V = 3.14 × 32

V = 100.48

Now you subtract the volume of the cone from the cylinder.

100.48 - 2.93 = 97.55

Rounded to the nearest tenth is 97.6

Hope this was helpful, I know it is a lot to look at but I tried my best.

Also, can I get brainliest? I worked really hard on this.

7 0
2 years ago
A 250-gal tank is initially filled with brine (salt-water mixture) containing 100 lb of salt. Brine containing 3 lb of salt per
gulaghasi [49]

Answer:

x(t) = 581.66 lb

Step-by-step explanation:

From the given information:

Consider the salt quantity in the tank at time t be x(t) lb.

∴ the rate of change of salt content in the tank is \dfrac{dx}{dt}= Rate \ of \  \ inflow - rate \ of \  \ outflow

where:

the rate of inflow = salt conc. × flow rate = 3 lb/gallon × 7 gallons

=21 lb/s

rate of outflow = salt conc. in the tank  × flow rate

= x/250 ×  9

= 9x/250  lb/s

∴

\dfrac{dx}{dt} = 21 - \dfrac{9x}{250}

\dfrac{dx}{dt} + \dfrac{9x}{250}= 21

This is a 1st order linear differentiation,

The integrating factor if e^{^{ \int \dfrac{9}{250}\ dt}} = e^{^{ \dfrac{9t}{250} }}

∴

e^{^{ \dfrac{9t }{250}}} \ \ x(t) = \int 21 e^{\dfrac{9t}{250}} \ dt + C

e^{^{ \dfrac{9t }{250}}} \ \ x(t) =  21 \times \dfrac{250}{9}e^{\dfrac{9t}{250}} + C

x(t) = \dfrac{1750}{3}+Ce^{^{\dfrac{-9t}{250}}}     at  t = (0) and x(0) = 100 lb

Hence;

100 = \dfrac{1750}{3}+C

C = \dfrac{1750}{3} -100

C = - \dfrac{1450}{3}

∴x(t) = \dfrac{1750}{3}-\dfrac{1450}{100}e^{^{\dfrac{-9t}{250}}}

after time t = 1 minute i.e 60 s

x(t) = \dfrac{1750}{3}-\dfrac{1450}{100}e^{^{\dfrac{-9 \times 60}{250}}}

x(t) = \dfrac{1750}{3}-\dfrac{1450}{100}e^{^{\dfrac{-540}{250}}}

x(t) = 581.66 lb

5 0
4 years ago
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