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leva [86]
3 years ago
13

A 15-ft A992 W10 x 54 beam-column is part of a braced frame and is subjected to a service dead load of 100 kips and a service li

ve load of 120 kips, as determined through a first-order analysis and the Direct Analysis Method. The loads are applied at the top of the vertical member with a horizontal eccentricity of 2 inches resulting in bending about the strong (x-x) axis of the section. Determine the adequacy of the member. Use LRFD. Use the approximate analysis method to account for second-order effects.

Engineering
1 answer:
8090 [49]3 years ago
5 0

Answer:

0.34

Explanation:

While talking about Load and Resistance Factor Design (LRFD) method, we can say that it is based on the principle that strength (resistance) of various materials is scaled down by some factors while the applied loads are scaled up by some factors, and thereby the structural elements are designed using reduced strength and increased loads.

Refer to attachment for the step by step solution.

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Water at 60°F passes through 0.75-in-internal diameter copper tubes at a rate of 1.2 lbm/s. Determine the pumping power per ft
Lelu [443]

Answer:

The pumping power per ft of pipe length required to maintain this flow at the specified rate 0.370 Watts

Explanation:

See calculation attached.

- First obtain the properties of water at 60⁰F. Density of water, dynamic viscosity, roughness value of copper tubing.

- Calculate the cross-sectional flow area.

- Calculate the average velocity of water in the copper tubes.

- Calculate the frictional factor for the copper tubing for turbulent flow using Colebrook equation.

- Calculate the pressure drop in the copper tubes.

- Then finally calculate the power required for pumping.

8 0
3 years ago
Create a package named one_dimensional_array and write a class that completes the following "OneDimensionalArrays" class. You wi
yan [13]

Answer:

The filled in codes are

1) private static int[] arr;

2)  int arr[] = new int[size_of_array];

        int increment = 100;

        for (int i = 0; i < size_of_array; i++) {

       arr[i] = increment * i;

       }

      return arr;

3) for (int i = 0; i < myArray.length; i++) {

      System.out.println(myArray[i]);

4)  OneDimensionalArrays result = new OneDimensionalArrays();

    result.createIntegers(num);

    result.printArray(arr);

Explanation:

Create a package named one_dimensional_array and write a class that completes the following "OneDimensionalArrays" class. You will complete the class by filling in code wherever you see the comment:

//******* FILL IN CODE *********

import java.util.Scanner;

public class OneDimensionalArrays {

   

   int[] createIntegers(int size_of_array)

   {

      //*******  FILL IN CODE *********

      // Your code will create an array of ints as large as specified in size_of_array

      // Fill the array in with the values: 0, 100, 200, 300, ....

      // Return the array that you just created

   }

   void printArray(int[] myArray)

   {

      //*******  FILL IN CODE *********

       // Print out your array with one number per line.  Get the size of the

       // array from the "myArray" parameter (no hard coding the size)

   }

   public static void main(String[] args) {

       Scanner keyboard = new Scanner(System.in);

       

       System.out.println("Enter size of array to create: ");

       int num = keyboard.nextInt();

       //*******  FILL IN CODE *********

       // Construct an instance of the OneDimensionalArrays class

       // Using this object instance, call createIntegers to create

       // an array of integers.  Don't forget to save the results

       // Then call the printArray method to print out the contents

       // of your array.

       }

}

Completed Code when filled in looks this way below:

import java.util.Scanner;

public class OneDimensionalArrays {

  private static int[] arr;

  int[] createIntegers(int size_of_array) {

       int arr[] = new int[size_of_array];

       int increment = 100;

       for (int i = 0; i < size_of_array; i++) {

             arr[i] = increment * i;    

       }

       return arr;

   }

   void printArray(int[] myArray) {

       for (int i = 0; i < myArray.length; i++) {

           System.out.println(myArray[i]);          

       }

   }

   public static void main(String[] args) {

       Scanner keyboard = new Scanner(System.in);

       System.out.println("Enter size of array to create: ");

       int num = keyboard.nextInt();

       OneDimensionalArrays result = new OneDimensionalArrays();

       result.createIntegers(num);

       result.printArray(arr);

   }

}

7 0
3 years ago
Compare and contrast mechanical properties of plastics, metals and ceramics.
IgorLugansk [536]

Answer:

free badge

Explanation:

6 0
2 years ago
Consider a process in which a carbon-based fuel is combusted in the presence of 70% excess oxygen (assume that all of the oxygen
yuradex [85]

Answer:

<u>Option-(A):</u>

  • When a carbon-based fuel is burned(combustion) or we can say burned in the presence of 70% excess oxygen (assuming that all of the oxygen present come from an air feel stream), we can say that there is 70% more oxygen present in the process that would be necessary for the complete combustion of all of the fuel.
  • Oxygen,O₂ is the precursor for the process of combustion as there is the requirement of an optimum level of oxygen for the burning up of the materials.While, there is about enough level of oxygen is present inside the free air or we can say inside the atmosphere for the purpose of combustion or burning of the fuel or consumption of the resources present in the environment.

7 0
4 years ago
25 An 8-bit computer uses 2's complement to store negative numbers. The range of numbers that can be
Inga [223]

Answer:

-128 to +127

Explanation:

8-bits = 2⁸ = 256 possible values

Half of those will be positive and the other half will be negative.

So 128 positive number and -128 negative numbers. But we must also include

the value 0, so now the range will be from -128 to 127

5 0
3 years ago
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