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DedPeter [7]
1 year ago
6

The source term will affect all algebraic equations.

Engineering
1 answer:
Drupady [299]1 year ago
8 0

The statement about the source term affecting all algebraic equations is; False

<h3>What is the source term in Algebraic Equations?</h3>

In the finite-element method of Analysis, we usually go from differential equations to a set of algebraic equations. Now, it is pertinent to note that each algebraic equation will tend to relate a nodal value with all other nodal values.

The assumed polynomial variation that will exist within each element is usually the basis for which we derive the algebraic equations. Thus, to derive the algebraic equations, we will have to assume a polynomial variation for the parameter values within each element.

The above can be done through interpolation of nodal parameter values in the post-processing stage. This is because the assumed polynomial variation within each element that is used for deriving the algebraic equations is also used for post-processing.

Finally, for each algebraic equation, the source term will tend to contribute to the coefficient that is taken to the right hand side of it and then entered into the corresponding row of the {f} vector.

Read more about Source Term at; brainly.com/question/28956378

#SPJ1

Complete Question is;

Select true or false.

The source term will affect all algebraic equations.

A.) True

B.) False

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\nu_{f} = 0.001080\,\frac{m^{3}}{kg}

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Since \nu_{f} < \nu < \nu_{g}, it is a liquid-vapor mixture. The quality of the mixture is:

x = \frac{\nu-\nu_{f}}{\nu_{g}-\nu_{f}}

x = \frac{0.2\,\frac{m^{3}}{kg} - 0.001080\,\frac{m^{3}}{kg} }{0.50850\,\frac{m^{3}}{kg} - 0.001080\,\frac{m^{3}}{kg} }

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The specific enthalpy is:

h = h_{f}+x\cdot (h_{g}-h_{f})

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h = 1429.74\,\frac{kJ}{kg}

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