The given question is incomplete as the equation given is not making sense.
From internet source i have taken the complete question and its been attached below.
The solution to the question is also attached in next image with complete detail.
<h3> I hope it will help you a lot!</h3>
Answer:
1) <em>4.41 * 10^-4 kw </em>
<em>2) </em>2.20 * 10^-4 kw
Explanation:
Given data:
Filter = 500 m^3/min
dust velocity = 3g/m^3
bag ; length = 3 m , diameter = 0.13 m
change in pressure = 1 kPa
efficiency = 60%
<u>1) Calculate the Fan power </u>
First :
Calculate the total dust loading = 3 * 500 = 1500 g
To determine the Fan power we will apply the relation
=
<em>fan power ( </em> )<em> = 4.41 * 10^-4 kw </em>
<u>2) calculate power drawn </u>
change in P = 6 atm = 6 * 10^5 pa
efficiency compressor = 50%
hence power drawn = 4.41 * 10^-4 kw * 50% = 2.20 * 10^-4 kw