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Rainbow [258]
3 years ago
8

Structural engineers, designing an eighty-story office building, need to account for sway. They would most likely use a(n) ____

Engineering
1 answer:
tia_tia [17]3 years ago
8 0

Answer:

I would say a level

Explanation:

A level is used as a horizontal reference line, which will tell if the building is leaning to one side, or if its up right. I may be wrong but this is the closest thing I can think of for this question.

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Question 7 of 10
exis [7]

Answer: Define the problem

Explanation: I just took the test

8 0
4 years ago
a cubical box 20-cm on a side is contructed from 1.2 cm thick concrete panels. A 100-W light bulb is sealed inside the box. What
Flura [38]

Answer:

Temperature on the inside ofthe box

Explanation:

The power of the light bulb is the rate of heat conduction of the bulb, dq/dt = 100 W

The thickness of the wall, L = 1.2 cm = 0.012m

Length of the cube's side, x = 20cm = 0.2 m

The area of the cubical box, A = 6x²

A = 6 * 0.2² = 6 * 0.04

A = 0.24 m²

Temperature of the surrounding, T_0 = 20^0 C = 273 + 20 = 293 K

Temperature of the inside of the box, T_{in} = ?

Coefficient of thermal conductivity, k = 0.8 W/m-K

The formula for the rate of heat conduction is given by:

dq/dt = \frac{kA(T_{in} - T_0)}{L} \\\\100 = \frac{0.8*0.24(T_{in} - 293)}{0.012}\\\\T_{in} - 293 = \frac{100 * 0.012}{0.8*0.24} \\\\T_{in} - 293 = 6.25\\\\T_{in} = 293 + 6.25\\\\T_{in} = 299.25 K\\\\T_{in} = 299.25 - 273\\\\T_{in} = 26.25^0 C

5 0
4 years ago
A pipe 100 mm dia and 1 km long is to carry water from a reservoir to a village of 1000 people consuming 200 l/person/day. The p
natka813 [3]

Answer:

i899999999999999999ijhhh

Explanation:

8 0
3 years ago
Read 2 more answers
A hollow, spherical shell with mass 2.00kg rolls without slipping down a slope angled at 38.0?.
mezya [45]

Answer:

\mu = 0.31

Explanation:

Given data:

mass = 2.00 kg

slope angle = 38.0

From figure

balancing force

mgsin\theta - f = ma   .....1

Balancing torque

F_R = \frac{2}{3} mR^2 \alpha ......2

for pure rolling

\alpha  = \frac{a}{R}

F = \frac{2}{3} ma

from 1 and 2nd equation

mgsin\theta - \frac{2}{3}ma =  ma

mgsin\theta = \frac{5}{3} ma

a = \frac{3}{5} g sin\theta

 = \frac{3\theta 9.8 sin 38}{5} = 3.62 m/s^2

F =\mu N

   = \frac{2}{3} ma

   = \frac{2}{3} 2\times 3.62 = 4.83 N

N =normal force =  mgsin\theta = 2 \times 9.8 sin 38 = 15.44 N

\mu \times 15.44 = 4.83

solving for  coefficent of friction we get

\mu = 0.31

4 0
3 years ago
Three masses are attached to a uniform meter stick, as shown in Figure 12.9. The mass of the meter
sp2606 [1]

At equilibrium, the sum of clockwise and anticlockwise moments about a point is zero

The mass of that balances the system is \underline {316.\overline 6} kg

The normal reaction force at the fulcrum is <u>5,804.25 N</u>

Rason:

The mass of the stick = 150.0 g

Mass m₁ on the left = 50.0 g, location = 30 cm to the left of m₂

Mass m₂ on the left = 75.0 g, location = 40 cm to the left of the fulcrum

Mass m₃ on the right of the fulcrum. location = 30 cm to the right of the fulcrum

Required:

To find the mass of m₃

Solution:

Taking moment about the fulcrum, we have;

50 × (30 + 40) + 75 × (40) + 150 × 20 = m₃ × 30

9,500 = m₃×30

m_3 = \dfrac{9,500}{30} = 316. \overline 6

The mass of that balances the system when it is attached at the right end of the stick, m₃ = 316.\overline 6 kg

Normal reaction at the fulcrum = (50 + 75 + 150 +  316.\overline 6) × 9.81 = 5804.25

The normal reaction at the fulcrum is 5,804.25 N

Learn more about the moment of a force here:

brainly.com/question/19464450

8 0
2 years ago
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