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Vesna [10]
3 years ago
9

What are Teets I am so confused right kn

Engineering
1 answer:
damaskus [11]3 years ago
3 0
A look, a glance, especially a quick or furtive one.
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Evaluate each of the following and express with an appropriate prefix: (a) (430 kg)^2 (b) (0.002 mg)^2, and (c) (230 m)^3
Mekhanik [1.2K]

Answer:

a)0.185g^2

b)4μg^2( Micrograms)

c)12.167hm^3( cubic hectometer)

Explanation:

To solve this problem, we must first use the calculator to solve each of the points, then knowing the number of zeros on the left or on the right, we choose a unit with which it is better to see the unit

A)

(430 kg)^2=184900kg^2=0.185g^2

B)

(0.002 mg)^2=4x10^-6mg^2=4μg( Micrograms)

c)

(230 m)^3=12167000m^3=12.167hm^3( hectometer)

6 0
3 years ago
How do you produce a well-constructed survey questionnaire?
Anni [7]

Answer:

Explanation:

Define the purpose of the survey.

Make every question count.

Keep it short and simple.

Ask direct questions.

Ask one question at a time.

Avoid leading and biased questions.

5 0
2 years ago
The two parking space configurations you'll see in garages and parking lots are _____.
den301095 [7]

Answer:

straight-in spaces and angle spaces  Hope this helps!

4 0
3 years ago
Read 2 more answers
Consider three branch prediction schemes: predict not taken, predict taken, and dynamic prediction. Assume that they all have ze
SOVA2 [1]

Answer:

Check the explanation

Explanation:

1. When a branch is taken with 5% frequency, the branch prediction scheme is "predict taken" because the process has to begin fetching and then execute at the target address.

2. When a branch is taken with 95% frequency, the branch prediction scheme is "predict not taken" because the branch outcome is definitely known.

3. When a branch is taken with 70% frequency, the prediction scheme is "dynamic prediction" the branch prediction can dynamically change during the program execution.

3 0
4 years ago
soccer is also called association football" A soccer ball is a sphere, with circumference of 70 centimeters. in developing a new
timama [110]

Answer: Weight on Mars = 0.02593N

Explanation:

Given; Circumference C of Sphere = 70cm = 0.7m,

Specific Gravity S. G. of material = 1.21,

acceleration due to gravity in the Mars gm = 3.7m/s^2

We know that Weight W = mass m × acceleration due to gravity.

Let the Weight in on the Mars be Wm.

Wm = m × gm

Since we are given gm, we need to calculate for m. (Note that mass m is the same everywhere)

But mass = specific gravity × volume

Since we know the specific gravity, let's go ahead to calculate for the volume of the ball.

We know that Volume of a Sphere V = (4/3)πr^3

To get r, we know that C = 2πr

Therefore, r = C/(2π) = 0.7/(2π) = (7/10)/2π = 7/20π (in meters)

V = (4/3)*π×(7/20π)^3 = 343/6000π^2 (in meter^3)

m = 343/6000π^2 × 1.21 = 7.01×10^(-3)kg

Wm = 7.01×10^(-3) × 3.7 = 0.02593N

8 0
3 years ago
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