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3 years ago

Who wants to do a zoom

Engineering

2 answers:

Arlecino [84]3 years ago

8 0

Wouldn’t recommend doing a zoom with anyone on here, some ppl are weirdos Imao but you do you.

ioda3 years ago

3 0

Answer:

HeY it's you again! (◕ᴗ◕✿)hello

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Dominic applies for a job in a robotics firm. One of the points in the job description is to have a good understanding of electr

pochemuha

Answer:

I Think It Is B

Explanation:

Because

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3 years ago

If a mineral fractures, how many directions of cleavage does it have?

Sveta_85 [38]

Answer:

Cleavage occurs in straight lines in a mineral, with different minerals exhibiting 1, 2, or 3 directions of cleavage. Fractures however are irregular and follow how specific pattern or cleavages

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3 years ago

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\o you sell them?” "Fivepence farthing for one—Twopence for two,” the Sheep replied. "Then two are cheaper than one?” Alice said

NemiM [27]

Answer:

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Explanation:

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3 years ago

Do not use C++ pointers (this is not a topic of this course).

noname [10]

The program is an illustration of functions in C++

C++ functions are collection of named program statements that are executed when called

<h3>The C++ program</h3>

The program in C++, where comments are used to explain each action is as follows:

#include <iostream>

#include <cmath>

using namespace std;

//This defines the boolean method

bool isoscelesTriangleHeightAndArea(double base, double hypotenuse, double height, double area) {

//This checks for invalid base and height

if(base < 0 || hypotenuse < 0){

return false;

}

//This returns true if base and height are valid

return true;

}

//The main begins here

int main(){

//This initializes the variables

double base, hypotenuse, height, area;

//This gets input for base and hypotenuse

cout<<"Base: "; cin>>base;

cout<<"Hypotenuse: "; cin>>hypotenuse;

//The calls the boolean method

bool success = isoscelesTriangleHeightAndArea(base, hypotenuse, height, area);

//If success is True

while (success){

//This calculates height

height = sqrt(hypotenuse*hypotenuse - (base/2) * (base/2));

//This calculates area

area = 0.5 * base * height;

//This prints height

cout << "Triangle height is " << height << endl;

//This prints area

cout << "Triangle area is " << area << endl;

//This gets input for base and hypotenuse

cout<<"Base: "; cin>>base;

cout<<"Hypotenuse: "; cin>>hypotenuse;

bool success = isoscelesTriangleHeightAndArea(base, hypotenuse, height, area);

}

cout << "Invalid Input!" << endl;

}

Read more about C++ programs at:

brainly.com/question/24833629

#SPJ1

4 0

2 years ago

1 kg of saturated steam at 1000 kPa is in a piston-cylinder and the massless cylinder is held in place by pins. The pins are rem

BARSIC [14]

Answer:

The final specific internal energy of the system is 1509.91 kJ/kg

Explanation:

The parameters given are;

Mass of steam = 1 kg

Initial pressure of saturated steam p₁ = 1000 kPa

Initial volume of steam, = V₁

Final volume of steam = 5 × V₁

Where condition of steam = saturated at 1000 kPa

Initial temperature, T₁ = 179.866 °C = 453.016 K

External pressure = Atmospheric = 60 kPa

Thermodynamic process = Adiabatic expansion

The specific heat ratio for steam = 1.33

Therefore, we have;

$\dfrac{p_1}{p_2} = \left (\dfrac{V_2}{V_1} \right )^k = \left [\dfrac{T_1}{T_2} \right ]^{\dfrac{k}{k-1}}$

Adding the effect of the atmospheric pressure, we have;

p = 1000 + 60 = 1060

We therefore have;

$\dfrac{1060}{p_2} = \left (\dfrac{5\cdot V_1}{V_1} \right )^{1.33}$

$P_2= \dfrac{1060}{5^{1.33}} = 124.65 \ kPa$

$\left [\dfrac{V_2}{V_1} \right ]^k = \left [\dfrac{T_1}{T_2} \right ]^{\dfrac{k}{k-1}}$

$\left [\dfrac{V_2}{V_1} \right ]^{k-1} = \left \dfrac{T_1}{T_2} \right$

$5^{0.33} = \left \dfrac{T_1}{T_2} \right$

T₁/T₂ = 1.70083

T₁ = 1.70083·T₂

T₂ - T₁ = T₂ - 1.70083·T₂

Whereby the temperature of saturation T₁ = 179.866 °C = 453.016 K, we have;

T₂ = 453.016/1.70083 = 266.35 K

ΔU = 3× $c_v$ ×(T₂ - T₁)

$c_v$ = cv for steam at 453.016 K = 1.926 + (453.016 -450)/(500-450)*(1.954-1.926) = 1.93 kJ/(kg·K)

cv for steam at 266.35 K = 1.86 kJ/(kg·K)

We use cv given by (1.93 + 1.86)/2 = 1.895 kJ/(kg·K)

ΔU = 3× $c_v$ ×(T₂ - T₁) = 3*1.895 *(266.35 -453.016) = -1061.2 kJ/kg

The internal energy for steam = $U_g = h_g -pV_g$

$h_g$ = 2777.12 kJ/kg

$V_g$ = 0.194349 m³/kg

p = 1000 kPa

$U_{g1}$ = 2777.12 - 0.194349 * 1060 = 2571.11 kJ/kg

The final specific internal energy of the system is therefore, $U_{g1}$ + ΔU = 2571.11 - 1061.2 = 1509.91 kJ/kg.

3 0

3 years ago