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3 years ago

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What is the area of this triangle? A=bh2 54 cm² 90 cm² 108 m² 216 m² Right triangle with height labeled 12 centimeters, base lab

eled 9 centimeters, and the third side labeled 15 centimeters.

1 answer:

inessss [21]3 years ago

7 0

Answer:54 idk though i forgot how to do this lol

Step-by-step explanation:

You might be interested in

Suppose that the position of one particle at time is given by x1=3sin t, y1 = 2 cos t, 0 ≤ t ≤ 2π and the position of a second p

Mashcka [7]

Answer:

there is no collision between the particles

Step-by-step explanation:

for the first particle

x1=3sin t, y1 = 2 cos t, 0 ≤ t ≤ 2π

for the second particle

x2 = -3 + cos t, y2 = 1 + sin t, 0 ≤ t ≤ 2π

then for the collision

x1=x2 → 3*sin t = -3 + cos t → sin t= -1 + (cos t)/3→ 1+ sin t = (1/3)cos t

y1=y2 → 1 + sin t = 2 cos t → (1/3)cos t = 2 cos t →(1/3) = 2

since 1/3 ≠ 2 there is no collision between the particles

6 0

3 years ago

Given that a 90% confidence interval for the mean height of all adult males in Idaho measured in inches was [62.532, 76.478]. Wh

NNADVOKAT [17]

Answer:

The point estimate used to estimate the mean height of all adult males in Idaho is 69.505 inches.

Step-by-step explanation:

Each confidence interval has two bounds, the lower bound and the upper bound. The points estimate used to estimate the mean is the halfway point between those two bounds, that is, the sum of those two bounds divided by two.

In this problem, we have that:

Lower bound: 62.532

Upper bound: 76.478

Point estimate: (62.532 + 76.478)/2 = 69.505

The point estimate used to estimate the mean height of all adult males in Idaho is 69.505 inches.

3 0

3 years ago

Needdd hellpppppssssssss

Ratling [72]

Answer:

Choice number one:

$\displaystyle \frac{5}{10}\cdot \frac{4}{9}$ .

Step-by-step explanation:

Let $A$ be the event that the number on the first card is even.
Let $B$ be the event that the number on the second card is even.

The question is asking for the possibility that event $A$ and $B$ happen at the same time. However, whether $A$ occurs or not will influence the probability of $B$ . In other words, $A$ and $B$ are not independent. The probability that both $A$ and $B$ occur needs to be found as the product of

the probability that event $A$ occurs, and
the probability that event $B$ occurs given that event $A$ occurs.

5 out of the ten numbers are even. The probability that event $A$ occurs is:

$\displaystyle P(A) = \frac{5}{10}$ .

In case A occurs, there will only be four cards with even numbers out of the nine cards that are still in the bag. The conditional probability of getting a second card with an even number on it, given that the first card is even, will be:

$\displaystyle P(B|A) = \frac{4}{9}$ .

The probability that both $A$ and $B$ occurs will be:

$\displaystyle P(A \cap B) = P(B\cap A) = P(A) \cdot P(B|A) = \frac{5}{10}\cdot \frac{4}{9}$ .

6 0

3 years ago

Eddie drank 3/4

ch4aika [34]

Answer:

3/4 x 5 = 15/20

3/5 x 4 = 12/20

15/20 + 12/20 = 27/20

Hope this helps!

6 0

3 years ago

zloy xaker [14]

1. false
2. true
3. true
4. true
5. what is GM
6. no
7. true
8. false

8 0

3 years ago