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den301095 [7]
2 years ago
5

It takes 3/8 of a gallon of paint to paint each dog house. How many doghouses can I paint with 6 gallons of paint?

Mathematics
1 answer:
Helga [31]2 years ago
5 0
You can paint 16 doghouses

Work: 3/8=.375 per doghouse
6/.375=16

Hope this helps!
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Answer pls urgent shhzhzhsensnsj
Strike441 [17]

Answer:

1/6 + 1/2 = 1/6 + 3/6 = 4/6

SIMPLIFIED IS = 2/3

Step-by-step explanation:

4 0
2 years ago
Which of the following numbers can be expressed as repeating decimals? 3 over 7, 2 over 5, 3 over 4, 2 over 9
Maurinko [17]

Hello!

Let's think about the denominators we have. A seventh goes on forever in no specified order. A fifth an a fourth have set decimal values, 0.2 and 0.25, so they are not repeating decimals. A ninth is 0.111111..., it repeats like this forever in a specified order. Therefore, 2/9, or 0.222222...., would be a repeating decimal.

Therefore, our answer is \boxed {\frac{2}{9}}.

I hope this helps!

6 0
3 years ago
HELP PLEASE <br><br>must show work <br><br>I have the answer just need to show work​
Kazeer [188]

Answer:

Step-by-step explanation:

To solve these equations involving variables and exponents we need to follow these steps.

1) We need to find out the factor that is common in the equation.

2) After taking common, solve the equation. We can add or subtract only those values that have same bases.

1) 8+6x^4

here we can see, both numbers are divisible by 2, so taking 2 common

=2(8/2 + 6x^4/2)\\= 2(4 + 3x^4)

It cannot be further simplified because both number donot have same bases.

3.4n^9 + 12 n

We can take 4n common

=4n(4n^9/4n + 12 n/4n)\\=4n(n^8 + 3)

5. -12a -3

Here -3 cam be taken common

= -3(-12a/-3 -3/-3)

= -3(4a +1)

7. 12n^5 + 16n^3

here the smallest power of n is n^3 so, we can take n^3 common and both coefficients are divisible by 4 so taking 4n^3 common

4n^3( 3n^2 + 4)

9. 5k^2 - 40k+10

Here we cannot take k common, as k is not a multiple of 10. For taking common it should be divisible by each value in the equation. But each value s divisible by 5 so, taking 5 common

=5(k^2 - 8k + 2)

11.-60 + 60n^2 +50n^3

Here we cannot take n common, as n is not a multiple of -60. For taking common it should be divisible by each value in the equation. But each value s divisible by 10 so, taking 10 common

=10(-6 + 6n^2 +5n^3)

13. -36n^3 -12n-28

Here we cannot take n common, as n is not a multiple of 28. For taking common it should be divisible by each value in the equation. But each value s divisible by -4 so, taking -4 common

=-4(9n^3 + 3n +7)

15. 63n^3+81n+18

Here we cannot take n common, as n is not a multiple of 18. For taking common it should be divisible by each value in the equation. But each value s divisible by 9 so, taking 9 common

=9(7n^3 + 9n + 2)

17. -24a^2b^2 + 36ab-60a

=6a(-4ab^2+6b-10)

3 0
3 years ago
Can somebody help me, please?
Sveta_85 [38]

Answer:

a.x=10 \textdegree

b.

m\angle L=39\textdegree\\\\m\angle M=51\textdegree\\\\m\angle K=90\textdegree

Step-by-step explanation:

a. We know that angles in a triangle add up to 180°.

-The right angle triangle in the right triangle has a measure of 90°.

We can therefore equate our angles to 180° and solve for x;

180=\perp\angle+(2x+19)+(3x+21)\\\\180=90+(2x+19)+(3x+21)\\\\90=5x+40\\\\5x=50\\\\x=10\textdegree

Hence, the angle measure is x=10°

b. Having calculated the value of x from a above as x=10°, we can substitute to find the measures of the two acute angles:

m\angle L=(2x+19)\textdegree\\\\=(2\times 10+19)\textdegree\\\\=39\textdegree\\\\m\angle M=(3x+21)\textdegree\\\\=(3\times 10+21)\textdegree\\\\=51\textdegree

Since, the m∠K is a right angle, it measures 90°

8 0
3 years ago
Which equation represents the data shown in the table below? Fence Length (y) 100 150 180 240 Number of Posts (x) 11 16 19 25 A
tensa zangetsu [6.8K]

Answer:y=10x-1

Step-by-step explanation:

5 0
3 years ago
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