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makkiz [27]
3 years ago
6

I need help with number 4 I mean k think I'm right

Chemistry
1 answer:
adell [148]3 years ago
5 0
Its b because it explains it better than a waterfall does
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How many grams of Cu(OH)2 will precipitate when excess NaOH solution is added to 46.0 mL of 0.584 M CuSO4
Slav-nsk [51]
<h3>Answer:</h3>

2.624 g

<h3>Explanation:</h3>

The equation for the reaction is given as;

  • CuSO₄(aq) + 2NaOH(aq) → Cu(OH)₂(s) + Na₂SO₄(aq)
  • Volume of CuSO₄ as 46.0 mL;
  • Molarity of CuSO₄ as 0.584 M

We are required to calculate the mass of Cu(OH)₂ precipitated

  • We are going to use the following steps;
<h3>Step 1: Calculate the number of moles of CuSO₄ used</h3>

Molarity = Number of moles ÷ Volume

To get the number of moles;

Moles = Molarity × volume

          = 0.584 M × 0.046 L

          = 0.0269 moles

<h3>Step 2: Calculate the number of moles of Cu(OH)₂ produced </h3>
  • From the equation 1 mole of CuSO₄ reacts to give out 1 mole of Cu(OH)₂
  • Therefore; Mole ratio of CuSO₄ to Cu(OH)₂ is 1 : 1.

Thus, Moles of CuSO₄ = Moles of Cu(OH)₂

Hence, moles of Cu(OH)₂ = 0.0269 moles

<h3>Step 3: Calculate the mass of Cu(OH)₂</h3>

To get mass we multiply the number of moles with the molar mass.

Mass = Moles × Molar mass

Molar mass of Cu(OH)₂ is 97.561 g/mol

Therefore;

Mass of Cu(OH)₂ = 0.0269 moles × 97.561 g/mol

                           = 2.624 g

Thus, the mass of Cu(OH)₂ that will precipitate is 2.624 g

3 0
3 years ago
. When 0.022189 is correctly rounded to two significant figures the number becomes
weeeeeb [17]
0.022
(Correct to two significant figures)
6 0
3 years ago
A chemist determines by measurements that moles of nitrogen gas participate in a chemical reaction. Calculate the mass of nitrog
Likurg_2 [28]

Answer:

0.56 g

Explanation:

<em>A chemist determines by measurements that 0.020 moles of nitrogen gas participate in a chemical reaction. Calculate the mass of nitrogen gas that participates.</em>

Step 1: Given data

Moles of nitrogen gas (n): 0.020 mol

Step 2: Calculate the molar mass (M) of nitrogen gas

Molecular nitrogen is a gas formed by diatomic molecules, whose chemical formula is N₂. Its molar mass is:

M(N₂) = 2 × M(N) = 2 × 14.01 g/mol = 28.02 g/mol

Step 3: Calculate the mass (m) corresponding to 0 0.020 moles of nitrogen gas

We will use the following expression.

m = n × M

m = 0.020 mol × 28.02 g/mol

m = 0.56 g

4 0
3 years ago
The standard cell potential Ec for the reduction of silver ions with elemental copper is 0.46V at 25 degrees celsius. calculate
Cloud [144]

Answer : The \Delta G for this reaction is, -88780 J/mole.

Solution :

The balanced cell reaction will be,  

Cu(s)+2Ag^+(aq)\rightarrow Cu^{2+}(aq)+2Ag(s)

Here, magnesium (Cu) undergoes oxidation by loss of electrons, thus act as anode. silver (Ag) undergoes reduction by gain of electrons and thus act as cathode.

The half oxidation-reduction reaction will be :

Oxidation : Cu\rightarrow Cu^{2+}+2e^-

Reduction : 2Ag^++2e^-\rightarrow 2Ag

Now we have to calculate the Gibbs free energy.

Formula used :

\Delta G^o=-nFE^o

where,

\Delta G^o = Gibbs free energy = ?

n = number of electrons to balance the reaction = 2

F = Faraday constant = 96500 C/mole

E^o = standard e.m.f of cell = 0.46 V

Now put all the given values in this formula, we get the Gibbs free energy.

\Delta G^o=-(2\times 96500\times 0.46)=-88780J/mole

Therefore, the \Delta G for this reaction is, -88780 J/mole.

7 0
3 years ago
2 Na + 1 Cl2 → 2 Naci<br> How many grams of NaCl are created from 23,2 grams Cl2?
evablogger [386]

37 grams of NaCl (when I mean equivalent I mean the ratio of the equation is 1:2 for moles or Cl2 and NaCl

3 0
2 years ago
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