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3 years ago

PLEASE HELP!! STOICHIOMETRY!

1 answer:

8 0

Now, if i remember this correctly, since i havent had a chemistry class in over 6 or so years

first you want the mass of baking powder in SI units,
why? -- well because molar mass unit conversions are generally in grams per mole
now, 1 oz = 28.3495 grams

now, assuming the "reactants" are the sodium ion and the hydrogen carbonate ion, you need to determine how many components of each will create one component of baking powder

well, if you look at the chemical compound, it requires one Na+ and one HCO3 -
hence the conversion would be 1 mol Na+ + 1 mol HCO3- ->1 mol NaHCO3

now, the big question is
I have 6oz of NaHCO3, but how many moles is that equal to?

now this is where molar mass is required (if you dont know what a mole is, i suggest looking it up, it has to do with a number of atoms in order to get a specific value)

now, the atomic weight of a sodium ion is 23 au
therefore the Molar mass of a sodium ion is 23 g/mol
the atomic weight of HCO3 is 61 au (i think)
hence the molar mass (MM) is 61 g/mol
the atomic weight of NaHCO3 is 84 au
hence the MM of NaHCO3 is 84 g/mol

now going back to the balanced equations
1 mol Na+ + 1 mol HCO3- ->1 mol NaHCO3
1 +1 ->1

but if we multiply each mol by its respective molar mass, we get
23 g Na+ + 61g HCO3- -> 84g NaHCO3

from here, if you wanted to find the amount of each "reactant" in oz,
its just a bunch of proportions

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How would you make a 2.00L of 0. 500M sodium chloride solution. (assume you have a fully equipped lab with water); sketch, calc

Gwar [14]

Answer:

Sodium chloride solution:

First you need to calculate the mass of salt needed (done in the explanation), which is 58.44g. Then it have to be weighted in an analytical balance in a weighting boat and then transferred into a 2L volumetric flask that is going to be filled until the mark with distilled water.

Sulfuric acid dilution:

First you need to calculate the volume needed (done in the explanation), it is 16.6 mL. Using a graduated pipette one measures this volume and transfer it into a 2L volumetric flask that is already half filled with distilled water, and then one fills it until its mark.

Explanation:

Sodium chloride solution:

Each liter of a 0.500M solution has half mol, so 2L of said solution has 1 mol of salt. Sodium chloride molar mass is 58.44g/mol, so in 2L of solution there is 58.44g of salt. That`s the mass that`s going to be weighted and transferred to a 2L volumetric flask.

Sulfuric acid dilution:

This is the equation for dilution of solutions:

$c_{1} v_{1} =c_{2} v_{2}$

Where "c1" stands for the initial concentration (stock solution concentration), "v1" for the initial volume (volume of stock solution used), "c2" for the desired concentration and "v2" for the desired volume.

When we are diluting from a stock solution we want to know how much do we have to pipette from the stock solution into our volumetric flask. We do so by isolating the "v1" term from the dilution equation:

$v_{1} =\frac{c_{2} v_{2} }{c_{1} }$

in this case that would be:

$v_{1} =\frac{0.100 x2.0 }{12.0 }=0.0166L=16.6mL$

5 0

3 years ago

Perform the following calculation and report the answer with the correct number of significant figures.

Paul [167]

Answer:

81.72 +0.73=82.45

Explanation:

you need to add it

81.72

+0.73

= 82.45

8 0

3 years ago

Read 2 more answers

What is the mass in grams of ba(io3)2 can be dissolved in 500 ml of water at 25 degrees celcius?

lesya [120]

The mass of Ba(IO3)2 that can be dissolved in 500 ml of water at 25 degrees celcius is 2.82 g

<h3>What mass of Ba(IO3)2 can be dissolved in 500 ml of water at 25 degrees celcius?</h3>

The Ksp of Ba(IO3)2 = 1.57 × 10^-9

Molar mass of Ba(IO3)2 = 487 g/mol?

Dissociation of Ba(IO3)2 produces 3 moles of ions as follows:

$Ba(IO_{3})_{2} \leftrightharpoons Ba^{2+} + 2\:IO_{3}^{-}$

$Ksp = [Ba^{2+}]*[IO_{3}^{-}]^{2}$

$[Ba(IO_{3})_{2}] = \sqrt[3]{ksp} =\sqrt[3]{1.57 \times {10}^{ - 9} } \\ [Ba(IO_{3})_{2}] = 1.16 \times {10}^{-3} moldm^{-3}$

moles of Ba(IO3)2 = 1.16 × 10^-3 × 0.5 = 0.58 × 10^-3 moles

mass of Ba(IO3)2 = 0.58 × 10^-3 moles × 487 = 2.82 g

Therefore, mass Ba(IO3)2 that can be dissolved in 500 ml of water at 25 degrees celcius is 2.82 g.

Learn more about mass and moles at: brainly.com/question/15374113

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