Ask question

Ask question

All categories

4 years ago

12

Which describes the image produced by a convex mirror? smaller than the object and right-side up smaller than the object and ups

ide down same size as the object and right-side up

1 answer:

inessss [21]4 years ago

6 0

Answer:Smaller Than the object and right-side up

Explanation:

You might be interested in

At a objects highest point is the acceleration zero too?

puteri [66]

Answer:

Acceleration from gravity is always constant and downward, but the direction and magnitude of velocity change. At the highest point in its trajectory, the ball has zero velocity, and the magnitude of velocity increases again as the ball falls back toward the earth

Explanation:

5 0

4 years ago

Read 2 more answers

1) A spring, which has a spring constant k=7.50 N/m, has been stretched 0.40 m from ts equilibrium position . What the potential

cupoosta [38]

<h3>Answer:</h3>

$\displaystyle U_s = 0.6 \ J$

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right<u> </u>

<u>Physics</u>

<u>Energy</u>

Elastic Potential Energy: $\displaystyle U_s = \frac{1}{2} k \triangle x^2$

U is energy (in J)
k is spring constant (in N/m)
Δx is displacement from equilibrium (in m)

<h3>Explanation:</h3>

<u>Step 1: Define</u>

k = 7.50 N/m

Δx = 0.40 m

<u>Step 2: Find Potential Energy</u>

Substitute in variables [Elastic Potential Energy]: $\displaystyle U_s = \frac{1}{2} (7.50 \ N/m) (0.40 \ m)^2$
Evaluate exponents: $\displaystyle U_s = \frac{1}{2} (7.50 \ N/m) (0.16 \ m^2)$
Multiply: $\displaystyle U_s = (3.75 \ N/m) (0.16 \ m^2)$
Multiply: $\displaystyle U_s = 0.6 \ J$

6 0

3 years ago

What is the formula for speed?

AlekseyPX

s = d/t

Speed = Distance divided by time

7 0

3 years ago

Read 2 more answers

In the image below, astronauts detect approaching space junk and become

Wewaii [24]

Answer:

A

Explanation:

7 0

3 years ago

Hey scooters dragging of 520 kg walk-through forest at a constant speed of 3.5 m/s. If the scooter is applying a force of 1850 N

Simora [160]

The coefficient of friction is 0.363

Explanation:

There are two forces acting on the scooter in the horizontal direction:

- The applied force, F = 1850 N, forward

- The frictional force, $F_f$ , backward

Since the scooter is moving at constant speed, the acceleration is zero, so the net force acting on the scooter must be zero. Therefore we can write:

$F-F_f = 0\\F_f = F = 1850 N$

The frictional force can be written as

$F_f = \mu R$ (1)

where

$\mu$ is the coefficient of friction

R is the normal reaction of the ground on the scooter

For a flat horizontal surface, there is equilibrium along the vertical direction, so the normal reaction is equal to the weight:

$R = W = mg$

where

m = 520 kg is the mass

$g=9.8 m/s^2$ is the acceleration of gravity

Substituting into (1),

$F_f = \mu mg = 1850 N$

and solving for $\mu$ ,

$\mu=\frac{F_f}{mg}=\frac{1850}{(520)(9.8)}=0.363$

Learn more about friction:

brainly.com/question/6217246

brainly.com/question/5884009

brainly.com/question/3017271

brainly.com/question/2235246

#LearnwithBrainly

5 0

4 years ago