Hey scooters dragging of 520 kg walk-through forest at a constant speed of 3.5 m/s. If the scooter is applying a force of 1850 N

Question

4 years ago

13

what is the coefficient of friction between a walk in the ground

1 answer:

Simora [160] · Answer 1 · 2022-02-18T23:35:46+03:00

The coefficient of friction is 0.363

Explanation:

There are two forces acting on the scooter in the horizontal direction:

- The applied force, F = 1850 N, forward

- The frictional force, $F_f$ , backward

Since the scooter is moving at constant speed, the acceleration is zero, so the net force acting on the scooter must be zero. Therefore we can write:

$F-F_f = 0\\F_f = F = 1850 N$

The frictional force can be written as

$F_f = \mu R$ (1)

where

$\mu$ is the coefficient of friction

R is the normal reaction of the ground on the scooter

For a flat horizontal surface, there is equilibrium along the vertical direction, so the normal reaction is equal to the weight:

$R = W = mg$

where

m = 520 kg is the mass

$g=9.8 m/s^2$ is the acceleration of gravity

Substituting into (1),

$F_f = \mu mg = 1850 N$

and solving for $\mu$ ,

$\mu=\frac{F_f}{mg}=\frac{1850}{(520)(9.8)}=0.363$

Learn more about friction:

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