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choli [55]
3 years ago
13

Hey scooters dragging of 520 kg walk-through forest at a constant speed of 3.5 m/s. If the scooter is applying a force of 1850 N

what is the coefficient of friction between a walk in the ground
Physics
1 answer:
Simora [160]3 years ago
5 0

The coefficient of friction is 0.363

Explanation:

There are two forces acting on the scooter in the horizontal direction:

- The applied force, F = 1850 N, forward

- The frictional force, F_f, backward

Since the scooter is moving at constant speed, the acceleration is zero, so the net force acting on the scooter must be zero. Therefore we can write:

F-F_f = 0\\F_f = F = 1850 N

The frictional force can be written as

F_f = \mu R (1)

where

\mu is the coefficient of friction

R is the normal reaction of the ground on the scooter

For a flat horizontal surface, there is equilibrium along the vertical direction, so the normal reaction is equal to the weight:

R = W = mg

where

m = 520 kg is the mass

g=9.8 m/s^2 is the acceleration of gravity

Substituting into (1),

F_f = \mu mg = 1850 N

and solving for \mu,

\mu=\frac{F_f}{mg}=\frac{1850}{(520)(9.8)}=0.363

Learn more about friction:

brainly.com/question/6217246

brainly.com/question/5884009

brainly.com/question/3017271

brainly.com/question/2235246

#LearnwithBrainly

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