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kvasek [131]
4 years ago
10

2+3 hhhhhhhhhjjjjjjjhhhh

Mathematics
2 answers:
igor_vitrenko [27]4 years ago
5 0
2 + 3 is 5 because 2 + 3, 2 ,3 ,4, 5 it = 5
Illusion [34]4 years ago
3 0
5
1 2 3 4 5

Hope it helps!
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Using the diagram below, where lines m and n are parallel, find the measure of a .
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Answer:

I think it is a I dont know

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3 years ago
In a school there are 60 teachers and 1200 students
Rufina [12.5K]

Answer:

409

Step-by-step explanation:

We first take the number of bilingual students 1200 * 0.3 = 400

Then the number of teachers 60 * 0.15 = 9

Add the two together and you have your answer

4 0
4 years ago
What is the original price of a hoverboard if it was marked up 80% and sold for final price of $300 (after mark-up).
victus00 [196]

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60

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7 0
3 years ago
Read 2 more answers
WILL MARK YOU BRAINLIEST
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<h3>Answer : 160</h3>

<h3>Explanation</h3>
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5 0
3 years ago
A sample of blood pressure measurements is taken for a group of adults, and those values (mm Hg) are listed below. The values ar
Kobotan [32]

Answer:

The coefficient of variation for the systolic measurements is 12.8 %

The coefficient of variation for the diastolic measurements is 16.3 %

Therefore, we can conclude that the systolic measurements are less dispersed as compared to diastolic measurements.

Step-by-step explanation:

The coefficient of variation is the ratio of standard deviation of the data to the mean of the data. It shows the dispersion in the data set.

Coefficient of variation for the systolic measurements:

Mean = μ = (120 + 128 + 156 + 98 + 154 + 122 + 118 + 136 + 128 + 120)/10

Mean = μ = 1280/10

Mean = μ = 128

Standard deviation = σ = \sqrt{\frac{1}{N}\sum_ (x-\mu)^{2} }

Using excel the standard deviation is found to be

Standard deviation = σ = 16.4

Coefficient of variation = σ/μ

Coefficient of variation = 16.4/128

Coefficient of variation = 0.128

Coefficient of variation = 12.8%

Coefficient of variation for the Diastolic measurements:

Mean = μ = (79 + 76 + 75 + 51 + 92 + 87 + 59 + 64 + 72 + 81)/10

Mean = μ = 736/10

Mean = μ = 73.6

Standard deviation = σ = \sqrt{\frac{1}{N}\sum_ (x-\mu)^{2} }

Using excel the standard deviation is found to be

Standard deviation = σ = 12

Coefficient of variation = σ/μ

Coefficient of variation = 12/73.6

Coefficient of variation = 0.163

Coefficient of variation = 16.3%

Conclusion:

We can conclude that the systolic measurements (12.8%) are less dispersed as compared to diastolic measurements (16.3%).

7 0
3 years ago
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