What is the range of f(x) = 3x + 9?

Mathematics

2 answers:

maw [93]3 years ago

7 0

We are given function f(x) = 3x+9.

We need to find the range of the given function.

We are given options

A) {y | y < 9}

B) {y | y > 9}

C) {y | y > 3}

D) {y | y < 3}

From the given options we can think that x is in the exponent of 3.

So, the given function is actually f(x) = 3^x +9

Now, we need to find the range of given function.

We can see that first term is and exponential term 3^x and second term is 9.

We know that 3^x will always be greater than 0.

<em>Therefore, 3^x +9 would always be greater than 9.</em>

<h3>Therefore, range would be y>9.</h3><h3>So, the correct option is B) {y | y > 9}.</h3>

aivan3 [116]3 years ago

4 0

The answer is b broskie

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shutvik [7]

Answer:

The 95% confidence interval would be given by (19.141;23.538)

Step-by-step explanation:

1) Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

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$\mu$ population mean (variable of interest)

s=9.22 represent the sample standard deviation

n=70 represent the sample size

2) Confidence interval

The confidence interval for the mean is given by the following formula:

$\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}$ (1)

In order to calculate the critical value $t_{\alpha/2}$ we need to find first the degrees of freedom, given by:

$df=n-1=70-1=69$

Since the Confidence is 0.95 or 95%, the value of $\alpha=0.05$ and $\alpha/2 =0.025$ , and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.025,69)".And we see that $t_{\alpha/2}=1.994$