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Alecsey [184]
3 years ago
11

Three observers watch a train pull away from a station toward the right of the platform. Observer A is in one of the train’s car

s; Observer B is on the station platform; and Observer C is on another train traveling in the opposite direction along a parallel track. How would the observer in each frame of reference describe the motion of the train? According to Newton’s laws of motion, how would the motion in the station platform’s frame of reference change if the conductor applied the brakes to the train? Does universal gravitation affect the train? Explain why or why not.
Physics
1 answer:
blagie [28]3 years ago
3 0

Describing motion from each frame of reference:

Since observer A is on one of the train's cars, he will find that he is at rest with respect to the train even when it is pulling away because,  he is also moving with respect to the train.

Observer B on the stationary platform will observe that the train is pulling away from the station towards the right of the platform. as is described


Observer C will notice that the train is approaching him in the opposite direction at a speed which is the sum of the speeds at which both the train are traveling


If the conductor applies brakes on the train, since the platform is a stationary frame of reference. The motion will be observed as a simple decelerationg. he will observe that the force due to the brakes will cause the velocity of the train with respect to the train to decrease


Universal law of gravitation effects all objects alike . There will be a constant force of gravity acting on the train that will keep the train on its tracks. The tracks in turn exert a reaction force on the train. There will not be any affect on the train's motion as such( assuming that the train is moving along the tracks and gravitational force is exactly perpendicular)

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Answer:

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Explanation:

Given

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All waves have same the relation among frequency, sound and speed which is given by

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Therefore, the speed of sound wave = 1000s^{-1} x 35 cm

                                                              = 35000 cms^{-1}

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Hence the speed of the sound wave is 350 ms^{-1}

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