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Alecsey [184]
3 years ago
11

Three observers watch a train pull away from a station toward the right of the platform. Observer A is in one of the train’s car

s; Observer B is on the station platform; and Observer C is on another train traveling in the opposite direction along a parallel track. How would the observer in each frame of reference describe the motion of the train? According to Newton’s laws of motion, how would the motion in the station platform’s frame of reference change if the conductor applied the brakes to the train? Does universal gravitation affect the train? Explain why or why not.
Physics
1 answer:
blagie [28]3 years ago
3 0

Describing motion from each frame of reference:

Since observer A is on one of the train's cars, he will find that he is at rest with respect to the train even when it is pulling away because,  he is also moving with respect to the train.

Observer B on the stationary platform will observe that the train is pulling away from the station towards the right of the platform. as is described


Observer C will notice that the train is approaching him in the opposite direction at a speed which is the sum of the speeds at which both the train are traveling


If the conductor applies brakes on the train, since the platform is a stationary frame of reference. The motion will be observed as a simple decelerationg. he will observe that the force due to the brakes will cause the velocity of the train with respect to the train to decrease


Universal law of gravitation effects all objects alike . There will be a constant force of gravity acting on the train that will keep the train on its tracks. The tracks in turn exert a reaction force on the train. There will not be any affect on the train's motion as such( assuming that the train is moving along the tracks and gravitational force is exactly perpendicular)

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American space pilots were called astronauts. What were soviet space pilots called?.
Mnenie [13.5K]

Answer:

Cosmonauts

Explanation:

As the americans are called astronauts which means <em>star sailors </em>and the <em>russians (soviet space pilots) are called cosmonauts</em> which means<em> sailors of the universe</em>

4 0
3 years ago
Church organs have a set of pipes with different lengths. With those different pipes organs can produce sounds over a wide range
Paraphin [41]

Answer: The shortest possible wavelength of sound the organ can produce is 0.224 m

Explanation:

To calculate the wavelength of light, we use the equation:

\lambda=\frac{c}{\nu}

where,

\lambda = wavelength of the light

c = speed of light = 331m/s

As wavelength and frequency follows inverse relation, shortest wavelength is produced by highest frequency.

\nu = highest frequency of light = 1.48kHz=1.48\times 10^3Hz=1.48\times 10^3s^{-1}       1Hz=1s^{-1}

\lambda=\frac{331m/s}{1.48\times 10^3s^{-1}}=0.224m

Thus the shortest possible wavelength of sound the organ can produce is 0.224 m

8 0
4 years ago
A ball is thrown straight up into the air with a speed of 21 m/s. If the ball has a mass of 0.1 kg, how high does the ball go? A
nirvana33 [79]

Hi!


The answer would be 22.5m

<h3>Explanation</h3>

To calculate the distance the ball travels, you would need to apply the following formula from the equations of motion for an accelerating object:

2as = v^2 - u^2

Where a is acceleration due to gravity, 9.8m/s^2

s is the distance traveled by the object (height of ball in this case)

v is the final velocity, which we know will be zero at the point where the ball reaches maximum height.

u is the initial velocity, which is known to us as 21m/s

Rearranging the equation to solve for the height:

s = (v^2 - u^2 ) / 2a

s = ( 0^2 - 21^2 ) / 2(-9.8)

s = - 441/ - 19.6

s = 22.5m


<em>Note: since gravity is acting against the object's motion, it will be negative </em>


<em>Hope this helps!</em>

6 0
3 years ago
Read 2 more answers
Help please!!
Ugo [173]

Answer:

B= 4 A=5

Explanation:

4 0
3 years ago
The mass of a typical froghopper is 12.3 mg . how many newtons does it weigh
Zinaida [17]
We are task to calculate for the weigh of a froghopper given only its mass of about 12.3 mg. To solve for this, we are going to use Newton's Second Law of Motion which in mathematical expression would be
F=ma
where F is the force acting on the object, m is the mass of an object and a is the acceleration acted on it.

Since the object is stationary, we assume the acceleration acted on it is in the vertical which is the acceleration due to gravity. Acceleration due to gravity is computed to be 9.81 m/s^{2}.

The unit of force is in Newton which equivalent to kg m/s^{2}.

We must convert mg to kg. We know that 1g=1000mg and 1kg=1000g.
For 12.3 mg=12.3mg x1g/1000mg x1kg/1000g =0.0000123 kg

To solve for the weigh,

F=0.0000123 kg x 9.81 m/s^{2}.
F=0.000121 N

Therefore, the weight of a froghopper in Newton is 0.000121N.
5 0
4 years ago
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