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Keith_Richards [23]

3 years ago

12

A 0.5 kg squirrel climbs a 75.0 m tall vertical maple tree. What must the squirrel’s average speed be in order to match the powe

r output of a 100 W lightbulb?

1 answer:

EleoNora [17]3 years ago

3 0

Answer:

Squirrel’s average speed = 277.78 m/s

Explanation:

Power of squirrel = 100 W

Mass of squirrel = 0.5 kg

Height climbed = 75 m

Potential energy = mgh = 0.5 x 9.81 x 75 = 367.875 J

We have

$\texttt{Power}=\frac{\texttt{Work}}{\texttt{Time}}$

Substituting

$100=\frac{367.875}{\texttt{Time}}\\\\\texttt{Time}=0.27s$

So squirrel need to cover 75 m in 0.27 s

Speed required

$v=\frac{75}{0.27}=277.78m/s$

Squirrel’s average speed = 277.78 m/s

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