The stage that comes first in the cycle of a high-mass star is :
C. Protostar
During this stage, the young Star is still gathering its mass from the residual of its parent molecular cloud
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The particles themselves do not change in size. When changing state the distance between the particles is what changes due to overcoming the intermolecular forces between the particles.
Answer:
Part a)
Part b)
Part c)
Explanation:
Part a)
As per energy conservation we can say
Energy stored in spring 1 = energy stored in spring 2
now we have
now from above equation
Part b)
To find the speed of the block we can say that its kinetic energy is gained due to spring energy
so we have
now we have
Part c)
When friction is present between two springs then we have energy loss due to friction force
so we have
now we have
Answer:
Approximately if that athlete jumped up at . (Assuming that .)
Explanation:
The momentum of an object is the product of its mass and its velocity . That is: .
Before the jump, the speed of the athlete and the earth would be zero (relative to each other.) That is: and . Therefore:
and .
Assume that there is no force from outside of the earth (and the athlete) acting on the two. Momentum should be conserved at the instant that the athlete jumped up from the earth.
Before the jump, the sum of the momentum of the athlete and the earth was zero. Because momentum is conserved, the sum of the momentum of the two objects after the jump should also be zero. That is:
.
Therefore:
.
.
Rewrite this equation to find an expression for , the speed of the earth after the jump:
.
The mass of the athlete needs to be calculated from the weight of this athlete. Assume that the gravitational field strength is .
.
Calculate using and values from the question:
.
The negative sign suggests that the earth would move downwards after the jump. The speed of the motion would be approximately .
A diverging lens is used to permit clear vision of an object placed at infinity. The focal length of the lens is -100 cm.
<h3>What is focal length?</h3>
The focal length is half of the radius of curvature of the focal lens.
By the lens maker formula,
1/f = 1/v +1/u
where, v is the image distance and u is the object distance.
Give, the object is at infinity and the image must form at 100 cm, the the focal length will be
1/f = 1/ -100 + 1/∞
f = -100 cm
The focal length must be -100 cm for the diverging lens.
Learn more about focal length.
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