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Stels [109]
4 years ago
15

What two things do i need to know to find velocity

Physics
2 answers:
mojhsa [17]4 years ago
6 0
Displacement and time
Lapatulllka [165]4 years ago
4 0
Hi! You would need to know: 

1) rate of change of position

<span>2) the direction of the displacement or change of position </span>
You might be interested in
Why the momentum is derived unit?​
Katena32 [7]

Answer:

Explanation:

Momentum: has a units of m*v.

mass is a primary unit (kg)

V: derived  it is made up of distance (meters) and seconds

7 0
3 years ago
Teenagers
Sophie [7]
A would be the best
5 0
3 years ago
1. If a 25 kg car accelerates at a speed of 100m/s2,2 what will the force of the car be?
algol13

Answer:

F = 2500N

Explanation:

F = ma

You're given m=25kg and a=100m/s²

Plug it in

F = (25)(100)

F = 2500N

4 0
4 years ago
A student pushes a laptop cart down the hallway by applying 20 Newtons force. The student pushes it 10 meters and
noname [10]

Answer:

None.

Explanation:

  • By definition, work is a process that it happens when an applied force

        causes an object to change its position, i.e. to have a displacement.

        Since the laptop cart is at rest while he stops at the water fountain, no  

       net work done is on the laptop cart.

4 0
3 years ago
Se dispara un proyectil con una velocidad inicial de 50 m/s y un ángulo de 30°, por encima de la horizontal. Calcular: a) Posici
dmitriy555 [2]

Answer:

a) Posición y velocidad después de los 6s

i) Posición = -26.58m

ii) velocidad = -33.86m/s

b) Tiempo para alcanzar la altura máxima

= 2.55s

c) Alcance horizontal

= 220.7m

Explanation:

a) Posición y velocidad después de los 6s

i) Posición

y = (usinθ)t – 1/2 gt²

u = 50m/s

θ = 30°

g = 9.81m/s²

t = 6s

y = (50 × sin 30)6 - 1/2 × 9.81 × 6²

y = 150 - 176.58

y = -26.58m

ii) velocidad

v = u sinθ–gt

u = 50m/s

θ = 30°

g = 9.81m/s²

t = 6s

v = 50 × sin 30 - 9.81 × 6

v = 25 - 58.86

v = -33.86m/s

b) Tiempo para alcanzar la altura máxima

usinθ /g

u = 50m/s

θ = 30°

g = 9.81m/s²

= 50 × sin 30/ 9.81

= 25/9.81

= 2.5484199796s

≈ 2.55s

c) Alcance horizontal

R = u²sin2θ/g

u = 50m/s

θ = 30°

g = 9.81m/s²

R = 50² ×( sin 2 ×30°) /9.81

R = 220.69964419m

≈ 220.7m

7 0
3 years ago
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