Church organs have a set of pipes with different lengths. With those different pipes organs can produce sounds over a wide range
1 answer:
Answer: The shortest possible wavelength of sound the organ can produce is 0.224 m
Explanation:
To calculate the wavelength of light, we use the equation:
where,
= wavelength of the light
c = speed of light =
As wavelength and frequency follows inverse relation, shortest wavelength is produced by highest frequency.
= highest frequency of light =
Thus the shortest possible wavelength of sound the organ can produce is 0.224 m
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Missing data in the text of the exercise: The molar concentration of Zinc is 10 times the molar concentration of copper.
Solution:
1) First of all, let's calculate the standard electrode potential difference at standard temperature. This is given by:
where
is the standard potential at the cathode, while 
is the standard potential at the anode. For a Daniel Cell, at the cathode we have copper: 
, while at the anode we have zinc: 
. Therefore, at standard temperature the electrode potential difference of the Daniel Cell is
2) To calculate
at any temperature T, we should use Nerst equation:
![E^0(T)=E^0- \frac{R T}{z F} \ln \frac{[Zn]}{[Cu]}](https://tex.z-dn.net/?f=E%5E0%28T%29%3DE%5E0-%20%5Cfrac%7BR%20T%7D%7Bz%20F%7D%20%5Cln%20%20%5Cfrac%7B%5BZn%5D%7D%7B%5BCu%5D%7D%20%20)
where
is the temperature in our problem
is the number of electrons transferred in the cell's reaction
is the Faraday's constant
![[Zn]](https://tex.z-dn.net/?f=%5BZn%5D)
and ![[Cu]](https://tex.z-dn.net/?f=%5BCu%5D)
are the molar concentrations of zinc and in copper, and in our problem we have ![[Zn]=10[Cu]](https://tex.z-dn.net/?f=%5BZn%5D%3D10%5BCu%5D)
.
Using all these data inside the equation, and using
, in the end we find:
![E^0(T)=E^0- \frac{R T}{z F} \ln \frac{[Zn]}{[Cu]}=+1.053 V](https://tex.z-dn.net/?f=E%5E0%28T%29%3DE%5E0-%20%5Cfrac%7BR%20T%7D%7Bz%20F%7D%20%5Cln%20%5Cfrac%7B%5BZn%5D%7D%7B%5BCu%5D%7D%3D%2B1.053%20V)
Solution:
1) First of all, let's calculate the standard electrode potential difference at standard temperature. This is given by:
where
2) To calculate
where
Using all these data inside the equation, and using
Answer:
The horizontal range will be
Explanation:
We have given initial speed of the shell u =
Angle of projection = 51°
Acceleration due to gravity
We have to find maximum range
Horizontal range in projectile motion is given by
So the horizontal range will be
Answer:
The value of the inductance is 1.364 mH.
Explanation:
Given;
amplitude current, I₀ = 200 mA = 0.2 A
amplitude voltage, V₀ = 2.4 V
frequency of the wave, f = 1400 Hz
The inductive reactance is calculated;
The inductive reactance is calculated as;
where;
L is the inductance
Therefore, the value of the inductance is 1.364 mH.