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sdas [7]
3 years ago
12

Church organs have a set of pipes with different lengths. With those different pipes organs can produce sounds over a wide range

of frequencies. If the lowest frequency produced by an organ is 30.4 Hz, and the highest frequency is 1.48 kHz, then what is the shortest possible wavelength of sound the organ can produce? Assume that the speed of sound is 331 m/s.
Physics
1 answer:
Paraphin [41]3 years ago
8 0

Answer: The shortest possible wavelength of sound the organ can produce is 0.224 m

Explanation:

To calculate the wavelength of light, we use the equation:

\lambda=\frac{c}{\nu}

where,

\lambda = wavelength of the light

c = speed of light = 331m/s

As wavelength and frequency follows inverse relation, shortest wavelength is produced by highest frequency.

\nu = highest frequency of light = 1.48kHz=1.48\times 10^3Hz=1.48\times 10^3s^{-1}       1Hz=1s^{-1}

\lambda=\frac{331m/s}{1.48\times 10^3s^{-1}}=0.224m

Thus the shortest possible wavelength of sound the organ can produce is 0.224 m

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Dima020 [189]

Answer:

B.

Explanation:

8 0
3 years ago
an object 24.0 cm from a concave mirror creates a virtual image at -33.5 cm. if the image is 7.25 cm tall, what is the height of
Hitman42 [59]

The height of the object will be -5.19 cm

A concave mirror's reflecting surface curves inward and away from the light source. Light is reflected inward to a single focus point via concave mirrors. Concave mirrors, in contrast to convex mirrors, produce a variety of images depending on the object's to the mirror.

Given an object 24.0 cm from a concave mirror creates a virtual image at -33.5 cm. if the image is 7.25 cm tall

So let,

v =  Image distance from the mirror = -33.5 cm

u = object distance from the mirror (concave) = 24 cm

hi = Image height = 7.25 cm

h = height of the object = ?

Using below formula to find height of the object

-v/u = hi/h

Putting all value in the formula we get

-(-33.5)/(-24) = 7.25/h

h = -5.19 cm

Therefore the height of the object will be -5.19 cm

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3 0
2 years ago
One of the reasons you love your home is because every side of your home faces South. One day, while talking on the phone, you h
ExtremeBDS [4]

The bear is white in color because it is a polar bear.

<h3>What are the color of bears?</h3>

Bears are very large carnivorous animals found around the cold regions of the Arctic or North Pole.

The color of bears, may be brown, black or white depending on how far North the bears are found.

Bears found close to the Arctic or North pole are white polar bears.

Based on the description of the house, every side of the home faces South meaning that the individual lives in the North pole.

Therefore, the color of the bear will be white.

in conclusion, polar bears are white in color.

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8 0
1 year ago
An electron enters a region with a speed of 5×10^6m/s and is slowed down at the rate of 1.25×10^-4m/s². How far does the electro
Mashutka [201]

1) The distance travelled by the electron is 1\cdot 10^{17} m

2) The time taken is 4.0\cdot 10^{10}s

Explanation:

1)

The electron in this problem is moving by uniformly accelerated motion (constant acceleration), so we can use the following suvat equation

v^2-u^2=2as

where

v is the final velocity

u is the initial velocity

a is the acceleration

s is the distance travelled

For the electron in this problem,

u=5\cdot 10^6 m/s is the initial velocity

v = 0 is the final velocity (it comes to a stop)

a=-1.25\cdot 10^{-4} m/s^2 is the acceleration

Solving for s, we find the distance travelled:

s=\frac{v^2-u^2}{2a}=\frac{0-(5\cdot 10^6)^2}{2(-1.25\cdot 10^{-4})}=1\cdot 10^{17} m

2)

The total time taken for the electron in its motion can also be found by using another suvat equation:

v=u+at

where

v is the final velocity

u is the initial velocity

a is the acceleration

t is the time taken

Here we have

u=5\cdot 10^6 m/s

v = 0

a=-1.25\cdot 10^{-4} m/s^2

And solving for t, we find the time taken:

t=\frac{v-u}{a}=\frac{0-5\cdot 10^6}{-1.25\cdot 10^{-4}}=4.0\cdot 10^{10}s

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7 0
3 years ago
a 250g moves eastward along a straight path at a constant velocity of 12 m per second calculate the momentum of the ball ​
lara31 [8.8K]

Explanation:

If two particles are involved in an elastic collision, the velocity of the second particle after collision can be expressed as: v2f=2⋅m1(m2+m1)v1i+(m2−m1)(m2+m1)v2i v 2 f = 2 ⋅ m 1 ( m 2 + m 1 ) v 1 i + ( m 2 − m 1 ) ( m 2 + m 1 ) v 2 i .

6 0
2 years ago
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