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Komok [63]
3 years ago
6

How much work is done by the force of gravity when a 15 kilogram rock falls off of a bridge 20 meters high?

Physics
1 answer:
viktelen [127]3 years ago
8 0
Work Done ( By Gravity) = Mg.H
= 15*10*20
=3 kJ
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Which term describes the forces on object with zero net force​
erik [133]

Answer:

50n

Explanation:

3 0
3 years ago
Pascal's Principle states that (a) If we apply pressure to a fluid in a sealed container, the pressure will be felt undiminished
nika2105 [10]

Answer:

a) If we apply pressure to a fluid in a sealed container, the pressure will be felt undiminished at every point in the fluid and on the walls of the container.

Explanation:

Pascal´s Principle can be applied in the hydraulic press:

If we apply a small force (F1) on a small area piston A1, then, a pressure (P) is generated that is transmitted equally to all the particles of the liquid until it reaches a larger area piston and therefore a force (F2) can be exerted that is proportional to the area(A2) of the piston.

P=F/A

P1=P2

F1/ A1= F2/ A2

F2= F1* A2/ A1

The pressure acting on one side is transmitted to all the molecules of the liquid because the liquid is incompressible.

In an incompressible liquid, the volume and amount of mass does not vary when pressure is applied.

5 0
3 years ago
When a slice of buttered toast is accidentally pushed over the edge of a counter, it rotates as it falls. If the distance to the
Serjik [45]

Answer:

a) 5.61 rad/s

b) 16.83 rad/s

Explanation:

Distance to the floor = 79cm = 0.79m

Rotation is <1 revolution

The toast will rotate at an angular speed that is constant while it falls. The toast will also be falling with constant acceleration due to gravity. Using equation of motion, which is

S = ut + 1/2gt²

S = 0 + 1/2gt²

S = gt², where, S = d

0.79 = 9.81t²

t² = 0.79/9.81

t² = 0.081

t = 0.28s

As the toast is accidentally pushed, it rotates as it falls. It will be landing on its edges when and if it hits the ground. The smallest angle here would then be 1/4 of the revolution. This is also the smallest angular speed.

ω(min) = ΔΦ revolution /Δt

ω(min) = 1/4 * 2π / 0.28

ω(min) = 0.5π/0.28

ω(min) = 5.61 rad/s

Since 1/4 of revolution is the minimum angle, the remaining(3/4), is the maximum angle. Thus

ω(max) = 3/4 * 2π / 0.28

ω(max) = 0.75 * 2π / 0.28

ω(max) = 16.83 rad/s

8 0
4 years ago
Read 2 more answers
The triceps muscle in the back of the upper arm extends the forearm.
iren [92.7K]

To solve this problem it is necessary to apply the concepts related to Torque as a function of Force and distance. Basically the torque is located in the forearm and would be determined by the effective perpendicular lever arm and force, that is

\tau = F \times r

Where,

F = Force

r = Distance

Replacing,

\tau = 2*10^3*0.03

\tau = 60N\cdot m

The moment of inertia of the boxer's forearm can be calculated from the relation between torque and moment of inertia and angular acceleration

\tau = I \alpha

I = Moment of inertia

\alpha = Angular acceleration

Replacing with our values we have that

I = \frac{\tau}{\alpha}

I = \frac{60}{120}

I = 0.5kg\cdot m^2

Therefore the value of moment of inertia is 0.5kg\cdot m^2

8 0
3 years ago
A 12 kg<br> mass is lifted to a height of 2 m. What is its potential energy<br> at this position?
Romashka-Z-Leto [24]

Answer:

Explanation:

Potential energy is the energy stored within an object, due to the object's position, arrangement or state

4 0
3 years ago
Read 2 more answers
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