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NARA [144]
3 years ago
5

Fill in the blanks. The electrostatic force between two objects is proportional to the ____________________ of the distance ____

________________.
Physics
2 answers:
Shkiper50 [21]3 years ago
6 0
Write an equation to calculate the force between two objects if the product of their charges is 10.0 × 10-4 C. (Note: Use the variable R for the distance between the charges.)

F = 900 ÷_________
Luba_88 [7]3 years ago
6 0

Answer:

The electrostatic force between two objects is proportional to the inverse of the square of the distance between the centres of the two objects

Explanation:

According to Coulomb's law of electrostatic attraction, the electrostatic force F between two charges or objects is directly proportional to the product of the absolute values of the charges or (charges on the objects) and inversely proportional to the square of their distance of separation.

Given that q_1 and q_2 are the charges or the charges on the objects, we can break down Coulomb's statement mathematically as follows;

F\alpha q_1q_2.............(1)  F is proportional to the product of the charges.

F\alpha \frac{1}{r^2}.......................(2) F is proportional to the inverse of the square of their distance r of separation.

This is an inverse-square relationship.

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Parker (73.2 kg) is being dragged down the hall with an applied force of 123 N. If the frictional force is 27.4 N, what is the c
levacccp [35]

Answer:

The coefficient of friction in the hall is 0.038

Explanation:

Given;

mass of the Parker, m = 73.2 kg

applied force on the parker, F = 123 N

frictional force, Fs = 27.4 N

the coefficient of friction in the hall = ?

frictional force is given by;

Fs = μN

Where;

μ is the coefficient of friction

N is normal reaction = mg

Fs = μmg

μ = Fs / mg

μ = (27.4) / (73.2 x 9.8)

μ = 0.038

Therefore, the coefficient of friction in the hall is 0.038

6 0
3 years ago
A= v50cm-v20cm<br> __________________<br> t
andrezito [222]

Answer:

.....?

Explanation:

did i help? NO ok.

3 0
3 years ago
A car accelerates uniformly from rest at a speed of 1.67 ft s^2 over a distance of 5 yards.What is the acceleration of a car?
Nina [5.8K]

Answer:

a= 17.69 m/s^2

Explanation:

Step one:

given data

A car accelerates uniformly from rest to 23 m/s

u= 0m/s

v= 23m/s

distance= 30m

Step two:

We know that

acceleration= velocity/time

also,

velocity= distance/time

23= 30/t

t= 30/23

t= 1.30 seconds

hence

acceleration= 23/1.30

accelaration= 17.69 m/s^2

5 0
2 years ago
Read 2 more answers
A child is holding a wagon from rolling straight back down in a driveway that inclined at 20 degree horizontal. if the wagon wei
Alenkinab [10]

Answer:

F = 51.3°

Explanation:

The component of weight parallel to the inclined plane must be responsible for the rolling back motion of the car. Hence, the force required to be applied by the child must also be equal to that component of weight:

F = Parallel\ Component\ of\ Weight\ of\ Wagon= WSin\theta\\

where,

W = Weight of Wagon = 150 N

θ = Angle of Inclinition = 20°

Therefore,

F = (150\ N)Sin\ 20^o

<u>F = 51.3°</u>

8 0
3 years ago
If the acceleration due to gravity at the surface of planet x is double the value of earth's, how does planet x's mass compare t
love history [14]
There is not enough information given to answer with. The force of gravity at the planet's surface depends on the planet's radius as well as its mass. The planet could have exactly the same mass as Earth has. But if it's radius is only 71% of Earth's radius, then gravity on its surface will be twice as strong as gravity on Earth.
3 0
4 years ago
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