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NARA [144]
3 years ago
5

Fill in the blanks. The electrostatic force between two objects is proportional to the ____________________ of the distance ____

________________.
Physics
2 answers:
Shkiper50 [21]3 years ago
6 0
Write an equation to calculate the force between two objects if the product of their charges is 10.0 × 10-4 C. (Note: Use the variable R for the distance between the charges.)

F = 900 ÷_________
Luba_88 [7]3 years ago
6 0

Answer:

The electrostatic force between two objects is proportional to the inverse of the square of the distance between the centres of the two objects

Explanation:

According to Coulomb's law of electrostatic attraction, the electrostatic force F between two charges or objects is directly proportional to the product of the absolute values of the charges or (charges on the objects) and inversely proportional to the square of their distance of separation.

Given that q_1 and q_2 are the charges or the charges on the objects, we can break down Coulomb's statement mathematically as follows;

F\alpha q_1q_2.............(1)  F is proportional to the product of the charges.

F\alpha \frac{1}{r^2}.......................(2) F is proportional to the inverse of the square of their distance r of separation.

This is an inverse-square relationship.

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A rock displaces 1.65 L of water. The volume of the rock is:
Oksanka [162]

Answer:

According to Archimedes principle, volume of water displaced = volume of water.

Hence volume of rock is = 1.65L or 1650 cm^3

Explanation:

7 0
3 years ago
A point charge q1q1 is held stationary at the origin. A second charge q2q2 is placed at point aa, and the electric potential ene
Yuri [45]

Explanation:

The given data is as follows.

            U_{a} = 5.4 \times 10^{-8} J

        W_{/text{a to b}} = -1.9 \times 10^{-8} J

        Electric potential energy (U_{b}) = ?

Formula to calculate electric potential energy is as follows.

            U_{b} = U_{a} - W_{/text{a to b}}

                        = 5.4 \times 10^{-8} J - (-1.9 \times 10^{-8} J)

                        = 7.3 \times 10^{-8} J

Thus, we can conclude that the electric potential energy of the pair of charges when the second charge is at point b is 7.3 \times 10^{-8} J.

6 0
3 years ago
How does the magnitude of the electrical force between a pair of charged particles change when they are brought to half their or
Ostrovityanka [42]

Answer:

5. Quadruple

Explanation:

The electrostatic force between two charged particles is given by:

F=k\frac{q_1 q_2}{r^2}

where

k is the Coulomb's constant

q1, q2 are the two charges

r is the separation between the charges

If the distance between the charges is reduced to half,

r' = \frac{r}{2}

So the new force will be

F'=k\frac{q_1 q_2}{(r/2)^2}=4(k\frac{q_1 q_2}{r^2})=4F

So, the force will quadruple.

4 0
3 years ago
What is the net force on this object?​
Mariulka [41]
Answer=8N

Explantion:
20-20=0
22-14=8N
5 0
3 years ago
__________ is when all light rays bounce off an object at the same angle.
Ad libitum [116K]
Diffuse reflection have a great day

5 0
2 years ago
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