The time when the two players will collide is 0.96 s.
The equation of motion of the two players is given as;
x1 = 0.1 m + (–3.9 m/s )t
x2 = –6.3 m + (2.8 m/s )t
The time when the two players collide, their displacement is equal or the difference in their position will be zero.

Thus, the time when the two players will collide is 0.96 s.
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Answer:
A. 40N
B. 5m/s
Explanation:
A.
Impulse is equal to the area under the curve of a force vs. time graph. In this case, the area is in the shape of a triangle with base 8 (12-4=8) and perpendicular height 10:
<em>Area of a triangle = (1/2)bh</em>
A=(1/2)*8*10
=40
ANSWER: 40N
B.
<em>Impulse = mass * velocity</em>
40 = 8v
v = 5
ANSWER: 5m/s
Answer:

Explanation:
It is given that,
Mass of the baseball, m = 0.14 kg
It is dropped form a height of 1.8 m above the ground. Let u is the velocity when it hits the ground. Using the conservation of energy as :

h = 1.8 m

u = 5.93 m/s
Let v is the speed of the ball when it rebounds. Again using the conservation of energy to find it :

h' = 1.4 m

v = -5.23 m/s
The change in the momentum of the ball is given by :



So, the change in the ball's momentum occurs when the ball hits the ground is 1.56 kg-m/s. Hence, this is the required solution.
Answer:
42.99°
Explanation:
= Kinetic friction force
= Pulling force at angle 
= Weight of the box = 150 N
Kinetic friction force

Pulling force at angle 

N = Pulling force
According to question

Applying Newton's second law in the vertical direction we get

The angle is 42.99°