Answer:
wrong question
Explanation:
unit of acceleration is written in m/s which is wrong
Answer:
A wishing well is a term from European folklore to describe wells where it was thought that any spoken wish would be granted. The idea that a wish would be granted came from the notion that water housed deities or had been placed there as a gift from the gods.
Explanation:
sources=wikipedia
The momentum, in the x-direction, that was transferred to the more massive cart after the collision is 19.38 kgm/s.
<h3>Momentum transfered to the more massive cart</h3>
The momentum transfered to the more massive cart is determined by applying the principle of conservation of linear momentum as shown below;
m₁u₁ + m₂u₂ = m₁v₁ + m₂v₂
where;
- m₁ is the mass of the smaller cart
- u₁ is the initial velocity of the samller cart
- m₂ is the mass of the bigger cart = 3m₁
- u₂ is the initial velocity of the bigger cart
- v₁ is the final velocity of the smaller cart
- v₂ is the final veocity of the bigger cart
⁻ΔP₁ = ΔP₂
ΔP₂ = m₂v₂ - m₂u₂
ΔP₂ = m₂(v₂ - u₂)
ΔP₂ = 3m₁(v₂ - u₂)
ΔP₂ = 3 x 3.8 x (1.7 - 0)
ΔP₂ = 19.38 kgm/s
Thus, the momentum, in the x-direction, that was transferred to the more massive cart after the collision is 19.38 kgm/s.
The complete question is beblow
A cart of mass 3.8 kg is traveling to the right (which we will take to be the positive x-direction for this problem) at a speed of 6.9 m/s. It collides with a stationary cart that is three times as massive. After the collision, the more massive cart is moving at a speed of 1.7 m/s, to the right.
Learn more about conservation of linear momentum here: brainly.com/question/7538238
Answer:
Explanation:
We can start from the known formula:
so we can write, since we want the initial velocity in terms of the ball's displacement, its acceleration in the vertical direction, and the elapsed time:
and for our values we have:
Power = (work done) / (time to do the work)
Work done = (force) / (distance moved in the direction of the force)
The work for the first mass is (5 kg) x (g) x (2 m) = 10g Joules.
The work for the 2nd mass is (10 kg) x (g) x (1 m) = 10g Joules.
as long as Jenna lifts both masses on the same planet, the amount of work is going to be the same in both cases. So in order to have the same power output, she would have to do both jobs in the same amount of time. If she did the first one in 3 seconds, then the second one also requires 3 seconds.
