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3 years ago

8

What does the equation n =Pout/Pin mean

2 answers:

V125BC [204]3 years ago

7 0

<span>Basically, the variable n is equal to the amount of P out of the system divided by the about of P into the system

</span>

alexandr1967 [171]3 years ago

4 0

<span>n= energy efficiency pout means output and pin means input the reason this would show efficiency is because your output should be greater then your input and because depending on how small your number is after your division will tell you how efficient it is you want a big number.</span>

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Just after a motorcycle rides off the end of a ramp and launches into the air, its engine is turning counterclockwise at 8325 re

alexgriva [62]

Answer:

$\frac{Ie}{lm} = 1.10*10^{-3}$

Explanation:

GIVEN DATA:

Engine operating speed nf = 8325 rev/min

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ratio of moment of inertia of engine to motorcycle is given as

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$\frac{Ie}{lm} = 1.10*10^{-3}$

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3 years ago

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A raging bull of mass 700 kg runs at 36 km/h .How much kinetic energy does it have ?

Ipatiy [6.2K]

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Are amplitude and wavelength related?<br> A: Yes<br> B: No

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2 years ago

The capacitor can withstand a peak voltage of 590 volts. If the voltage source operates at the resonance frequency, what maximum

kirill115 [55]

Answer:

The maximum voltage is 41.92 V.

Explanation:

Given that,

Peak voltage = 590 volts

Suppose in an L-R-C series circuit, the resistance is 400 ohms, the inductance is 0.380 Henry, and the capacitance is $1.20×10^{-2}\ \mu F$ .

We need to calculate the resonance frequency

Using formula of frequency

$f=\dfrac{1}{2\pi\sqrt{LC}}$

Put the value into the formula

$f=\dfrac{1}{2\pi\sqrt{0.380\times1.20\times10^{-8}}}$

$f=2356.88\ Hz$

We need to calculate the maximum current

Using formula of current

$I=\dfrac{V_{c}}{X_{c}}$

$I=2\pi\times f\times C\times V_{c}$

$I=2\pi\times2356.88\times1.20\times10^{-8}\times590$

$I=0.1048\ A$

Impedance of the circuit is

$z=\sqrt{R^2+(X_{L}^2-X_{C}^2)}$

At resonance frequency $X_{L}=X_{C}$

$Z=R$

We need to calculate the maximum voltage

Using ohm's law

$V=I\times R$

$V=0.1048\times400$

$V=41.92\ V$

Hence, The maximum voltage is 41.92 V.

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3 years ago