All categories

3 years ago

What does the equation n =Pout/Pin mean

2 answers:

7 0

Basically, the variable n is equal to the amount of P out of the system divided by the about of P into the system

alexandr1967 [171]3 years ago

4 0

n= energy efficiency pout means output and pin means input the reason this would show efficiency is because your output should be greater then your input and because depending on how small your number is after your division will tell you how efficient it is you want a big number.

You might be interested in

Information about mars' moons.

Alex

Answer:

mars is a fourth planet of the sun and the second planet in the solar system

moon is a natural satellite of the earth it isthe fifth largest moon in the solar system

6 0

2 years ago

Which of the following equations illustrates the law of conservation of matter?

Anvisha [2.4K]

Answer:

Explanation:

the balancing is correct in the first one

8 0

3 years ago

The power supplies in 1206 Mudd feature an internal protection mechanism that limits the output current to 1 ampere (oh no, not

Art [367]

Answer:

thanks for the points

Explanation:

7 0

3 years ago

Calculate the wavelength of the electromagentic waves with the given frequencies, and determine the type of electromagnetic radi

ololo11 [35]

To develop this problem we require the concepts related to wavelength and its expression to calculate it.

The wavelength is given by

$\lambda =\frac{c}{f}$

Where,

$c=3*10^8 m/s$ light velocity

f = frequency.

Our values are given by,

$f_1=4.38*10^{14}Hz$

$f_2= 4.14*10^{20}Hz$

$f_3 = 3.24*10^{12}Hz$

Then,

$\lambda_1=\frac{3*10^8}{4.38*10^{14}}= 6.8493*10^{-7}m$ Visible

$\lambda_2=\frac{3*10^8}{4.14*10^{20}}= 7.24*10^{-13}m$ Gamma Ray

$\lambda_3=\frac{3*10^8}{3.24*10^{12}}= 9.259*10^{-5}m$ Infrared

*Note the designation on the type of rays that are, can be found in consulted via On-line or in the optical books referring to the electromagnetic spectrum table with their respective ranges.

5 0

4 years ago

a mass of 0.30kg is attached to a spring and is set in motion with a period of 0.24 s. what is the spring constantof the spring

IrinaK [193]

Answer:

The spring constant of the spring is 205.42 N/m.

Explanation:

Springs have their own natural "spring constants" that define how stiff they are. The letter k is used for the spring constant, and it has the units N/m.

k = -F/x

The period of a spring-mass system is proportional to the square root of the mass and inversely proportional to the square root of the spring constant.

Given:

mass of object in SHM = m = 0.30 kg

Time period of the spring mass system = 0.24s

Spring constant = k ?

Finding 'k' using Time period 'T':

We know that $T = 2pi\sqrt{\frac{m}{k} }$

$\frac{T}{2pi} = \sqrt{\frac{m}{k} }\\ \frac{T^{2} }{4(3.14)^{2} } = \frac{m}{k}\\ k = \frac{m*4*9.86}{T^{2} } \\k = \frac{0.3*4*9.86}{0.24^{2}}\\k = 205.42 N/m}$

8 0

3 years ago