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3 years ago

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What kind of research in teaching of physical science can be done???

1 answer:

11Alexandr11 [23.1K]3 years ago

3 0

Answer:

Physical sciences are those academic disciplines that aim to uncover the underlying laws of nature - often written in the language of mathematics. It is a collective term for areas of study including astronomy, chemistry, materials science and physics.

Explanation:

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Objects 1 and 2 attract each other with a gravitational force of 72.0 units. If the mass of Object 1 is one-fourth the original

Black_prince [1.1K]

Answer:

New gravitational force, F' = 216 units

Explanation:

Given that,

Gravitational force between object 1 and 2, F = 72 N

The gravitational force between two objects is given by :

$F=\dfrac{Gm_1m_2}{r^2}$

$\dfrac{Gm_1m_2}{r^2}=72$ ............(1)

If the mass of object 1, $m_1'=\dfrac{m_1}{4}$

$m_2'=3m_2$

If the distance between objects is halved, $r'=\dfrac{r}{2}$

Let new gravitational force is F'. It is changed to :

$F=\dfrac{Gm'_1m'_2}{r'^2}$

$F'=\dfrac{G\times \dfrac{m_1}{4}\times 3m_2}{(\dfrac{r}{2})^2}$

$F'=3\times \dfrac{Gm_1m_2}{r^2}$

$F'=3\times F$

$F'=3\times 72$

F' = 216 units

So, the new gravitational force will be 216 units.

6 0

3 years ago

skateboarder, starting from rest, rolls down a 13.5 m ramp. When she arrives at the bottom of the ramp her speed is 7.37 m/s. If

scZoUnD [109]

Answer:

1.7 m/s²

Explanation:

d = length of the ramp = 13.5 m

v₀ = initial speed of the skateboarder = 0 m/s

v = final speed of the skateboarder = 7.37 m/s

a = acceleration

Using the equation

v² = v₀² + 2 a d

7.37² = 0² + 2 a (13.5)

a = 2.01 m/s²

θ = angle of the incline relative to ground = 29.9

a' = Component of acceleration parallel to the ground

Component of acceleration parallel to the ground is given as

a' = a Cosθ

a' = 2.01 Cos29.9

a' = 1.7 m/s²

7 0

3 years ago

A disk with a uniform positive surface charge density lies in the x-y plane, centered on the origin. The disk contains 2.5 x 10-

allochka39001 [22]

Answer:

E=3 x 10^4 N/c

Explanation:

The electric field strength can be found out disk with a uniform positive surface charge density by

$E= (\sigma/\2epsilon_o)(1-z/ \sqrt(z^2+r^2))$

σ= charge density

r= radius of the disk

z= position in which we have to find electric field = 15 cm

ε_0= constant ( vacuum permitivity)

putting values we get

$E= \frac{2.5\times10^{-6}}{2\times2.5\times10^{-6}}(1-\frac{0.15}{\sqrt{0.15^2+0.075^2} })$

solving we get

E=30000 N/c

E=3 x 10^4 N/c

6 0

3 years ago

How does mass affect acceleration during free fall?

nirvana33 [79]

The first one, as the mass is higher so it accelerates more

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3 years ago

A child uses her hand to measure the width of a table too. Her hand has a width of 6.9 cm at its widest points, and she finds th

daser333 [38]

20/45/1 step by step explanation

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3 years ago