Answer:
You greatest common factor is
![3t^{2}](https://tex.z-dn.net/?f=3t%5E%7B2%7D)
Step-by-step explanation:
You need to find a number and letter which goes into both monomials.
,![3t^{2}](https://tex.z-dn.net/?f=3t%5E%7B2%7D)
Split both monomials up, into each integer and letter.
INTERGERS: 6, 3
LETTER t:
,![t^{2}](https://tex.z-dn.net/?f=t%5E%7B2%7D)
LETTER z: ![z^{5}](https://tex.z-dn.net/?f=z%5E%7B5%7D)
3 goes into 6 and 3.
goes into
and
.
Nothing goes into
and 0.
You greatest common factor is
![3t^{2}](https://tex.z-dn.net/?f=3t%5E%7B2%7D)
Therefore
![3t^{2} (tz^{5} , 1) = 3t^{3}z^{5} ,3t^{2}](https://tex.z-dn.net/?f=3t%5E%7B2%7D%20%28tz%5E%7B5%7D%20%2C%201%29%20%3D%203t%5E%7B3%7Dz%5E%7B5%7D%20%2C3t%5E%7B2%7D)
Answer:
2996
Step-by-step explanation:
5x + 4x = 6741
9x = 6741
x = 6741/9
x = 749
to get the no votes,
4x i.e 4*749
=> 4*749 = 2996
hope this helps :)
5. 2430 because in a trapezoid 2 if the lengths are the same and 2 are different, so you do 9*9*5*6=2430
The airplane went 5195.33 km
Step-by-step explanation:
Distance = speed × time
The given is:
1. An airplane flies for 3.5 hours with a constant speed of 840 km/h
2. Then for another 3 hours 19 minutes with a constant speed of
680 km/h
We need the distance it traveled
For the first part
∵ The time is 3.5 hours
∵ The speed is 840 km/h
∵ Distance = speed × time
- Substitute the values of the speed and the time in the rule
∴ Distance = 840 × 3.5
∴ Distance = 2940 km
For the second part
∵ The time is 3 hours and 19 minutes
- We must change the minutes to hour
∵ 1 hour = 60 minutes
∴ 19 minutes =
hour
∴ The time is
hour
∵ The speed is 680 km/h
∴ Distance = 680 × ![3\frac{19}{60}](https://tex.z-dn.net/?f=3%5Cfrac%7B19%7D%7B60%7D)
∴ Distance =
km
∴ The total distance = 2940 + ![2255\frac{1}{3}](https://tex.z-dn.net/?f=2255%5Cfrac%7B1%7D%7B3%7D)
∴ The total distance =
km
It went 5195.33 km
Learn more:
You can learn more about constant speed in brainly.com/question/568302
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