Both cylinder are similar
Volume of a cylinder is πr^2h
if we consider both has same radius as they are similar
Lets say V1 is volume of small cylinder and V2 is volume of big cylinder.
V1/V2=πr^2x5/πr^2xh
125/343=5/h
0.36=5/h
h=5/0.36
h=13.72 ft
substitution and elimination means that you need to use one equation and substitute it in place of some variable in the other equation.
Consider the above two equations.
Take equation 1, which is 4x-2y=22 => x=(22+2y)/4
substitute the x value gained above in equation 2.
so, 2((22+2y)/4)+4y=6
22+2y+8y=12 => 10y = -10 => y= -1.
Substitute y= -1 in x value obtained in the beginning.
So, x= (22 - 2)/4 => 5.
There fore, x= 5 and y= -1
Hope it helps.
Answer:
2m+12
Step-by-step explanation:
add like terms
2m+12
Answer:
216
Step-by-step explanation:
